**Title: Boiling Point Elevation and Molality Calculation****Text:**The boiling point of water is **100.00 °C** at 1 atmosphere.A student dissolves **11.57 grams** of **manganese(II) iodide, MnI₂ (308.7 g/mol)**, in **221.5 grams** of water. Use the table of boiling and freezing point constants to answer the questions below.**Table of Boiling and Freezing Point Constants:**| Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) ||--------------|----------------|------------------|------------------|| Water | \( H_2O \) | 0.512 | 1.86 || Ethanol | \( CH_3CH_2OH \) | 1.22 | 1.99 || Chloroform | \( CHCl_3 \) | 3.67 | - || Benzene | \( C_6H_6 \) | 2.53 | 5.12 || Diethyl ether| \( CH_3CH_2OCH_2CH_3 \) | 2.02 | - |**Questions:**1. **The molality of the solution is ____ m.**2. **The boiling point of the solution is ____ °C.**### Explanation and Step-by-Step Solution:To solve the problems, follow these steps:**Step 1: Calculate the Molality of the Solution**Molality (m) is defined as the moles of solute per kilogram of solvent.1. **Find the moles of manganese(II) iodide (MnI₂):** - Molar mass of MnI₂ = 308.7 g/mol - Mass of MnI₂ = 11.57 g \[ \text{Moles of MnI₂} = \frac{\text{Mass}}{\text{Molar Mass}} = \frac{11.57 \text{ g}}{308.7 \text{ g/mol}} = 0.0375 \text{ mol} \]2. **Convert the mass of the solvent (water) to kilograms:** - Mass

Answered: Image /qna-images/answer/914b0b5e-f3fd-424f-a63a-3569a1cd30cc.jpg

The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 11.57 grams of manganese(II) iodide, MnI, (308.7 g/mol), in 221.5 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kp (°C/m) Kf (°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH2OCH,CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.

The boiling point of water is 100.00 °C at 1 atmosphere. A student dissolves 11.57 grams of manganese(II) iodide, MnI, (308.7 g/mol), in 221.5 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula Kp (°C/m) Kf (°C/m) Water H20 0.512 1.86 Ethanol CH3CH2OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH2OCH,CH3 2.02 The molality of the solution is m. The boiling point of the solution is °C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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