The freezing point of water is 0.00 °C at 1 atmosphere. A student dissolves 13.58 grams of sodium bromide, NaBr (102.9 g/mol), in 259.0 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Formula Kb(°C/m) Kf(°C/m) Solvent Water H₂O 0.512 Ethanol CH3 CH₂OH 1.22 Chloroform CHCl3 3.67 Benzene C6H6 2.53 Diethyl ether |CH3 CH₂ OCH₂ CH3 2.02 The molality of the solution is The freezing point of the solution is m. °C. 1.86 1.99 5.12

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The freezing point of water is 0.00 °C at 1 atmosphere.

A student dissolves 13.58 grams of sodium bromide, NaBr (102.9 g/mol), in 259.0 grams of water. Use the table of boiling and freezing point constants to answer the questions below.

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### Table: Boiling and Freezing Point Constants

| Solvent        | Formula          | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|----------------|------------------|------------------|------------------|
| Water          | \( \text{H}_2\text{O} \)         | 0.512            | 1.86             |
| Ethanol        | \( \text{CH}_3\text{CH}_2\text{OH} \)   | 1.22             | 1.99             |
| Chloroform     | \( \text{CHCl}_3 \)         | 3.67             | —                |
| Benzene        | \( \text{C}_6\text{H}_6 \)           | 2.53             | 5.12             |
| Diethyl ether  | \( \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \) | 2.02             | —                |

---

**Calculation:**

The molality of the solution is \(\_\_\_\_\_\) m.

The freezing point of the solution is \(\_\_\_\_\_\) °C.
Transcribed Image Text:The freezing point of water is 0.00 °C at 1 atmosphere. A student dissolves 13.58 grams of sodium bromide, NaBr (102.9 g/mol), in 259.0 grams of water. Use the table of boiling and freezing point constants to answer the questions below. --- ### Table: Boiling and Freezing Point Constants | Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) | |----------------|------------------|------------------|------------------| | Water | \( \text{H}_2\text{O} \) | 0.512 | 1.86 | | Ethanol | \( \text{CH}_3\text{CH}_2\text{OH} \) | 1.22 | 1.99 | | Chloroform | \( \text{CHCl}_3 \) | 3.67 | — | | Benzene | \( \text{C}_6\text{H}_6 \) | 2.53 | 5.12 | | Diethyl ether | \( \text{CH}_3\text{CH}_2\text{OCH}_2\text{CH}_3 \) | 2.02 | — | --- **Calculation:** The molality of the solution is \(\_\_\_\_\_\) m. The freezing point of the solution is \(\_\_\_\_\_\) °C.
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