The freezing point of water is 0.00°C at 1 atmosphere. A student dissolves 12.27 grams of sodium acetate, NaCH3C00 (82.00 g/mol), in 174.4 grams of water. Use the table of boiling and freezing point constants to answer the questions below. Solvent Formula K, °C/m) KfCC/m) Water H20 0.512 1.86 Ethanol CH;CH,OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene CH6 2.53 5.12 Diethyl ether CH3CH;0CH,CH; 2.02 The molality of the solution is | m. The freezing point of the solution is °C.

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**Text Transcription and Explanation**

The freezing point of water is 0.00°C at 1 atmosphere.

A student dissolves 12.27 grams of sodium acetate, NaCH₃COO (82.00 g/mol), in 174.4 grams of water. Use the table of boiling and freezing point constants to answer the questions below.

**Table of Solvents and Constants**

| Solvent        | Formula          | \( K_b \) (°C/m) | \( K_f \) (°C/m) |
|----------------|------------------|------------------|------------------|
| Water          | H₂O              | 0.512            | 1.86             |
| Ethanol        | CH₃CH₂OH         | 1.22             | 1.99             |
| Chloroform     | CHCl₃            | 3.67             | —                |
| Benzene        | C₆H₆             | 2.53             | 5.12             |
| Diethyl ether  | CH₃CH₂OCH₂CH₃    | 2.02             | —                |

**Questions:**

1. The molality of the solution is __________ m.

2. The freezing point of the solution is __________ °C.

**Explanation of the Table:**

The table provides the boiling point elevation constants (\( K_b \)) and freezing point depression constants (\( K_f \)) for various solvents. 

- **Water (H₂O):** has a \( K_b \) of 0.512°C/m and a \( K_f \) of 1.86°C/m.
- **Ethanol (CH₃CH₂OH):** has a \( K_b \) of 1.22°C/m and a \( K_f \) of 1.99°C/m.
- **Chloroform (CHCl₃):** only provides a \( K_b \) of 3.67°C/m.
- **Benzene (C₆H₆):** has a \( K_b \) of 2.53°C/m and a \( K_f \) of 5.12°C/m.
- **Diethyl ether (CH₃CH₂OCH₂CH₃):** only provides a \( K_b \) of 2.02°C/m.

These constants
Transcribed Image Text:**Text Transcription and Explanation** The freezing point of water is 0.00°C at 1 atmosphere. A student dissolves 12.27 grams of sodium acetate, NaCH₃COO (82.00 g/mol), in 174.4 grams of water. Use the table of boiling and freezing point constants to answer the questions below. **Table of Solvents and Constants** | Solvent | Formula | \( K_b \) (°C/m) | \( K_f \) (°C/m) | |----------------|------------------|------------------|------------------| | Water | H₂O | 0.512 | 1.86 | | Ethanol | CH₃CH₂OH | 1.22 | 1.99 | | Chloroform | CHCl₃ | 3.67 | — | | Benzene | C₆H₆ | 2.53 | 5.12 | | Diethyl ether | CH₃CH₂OCH₂CH₃ | 2.02 | — | **Questions:** 1. The molality of the solution is __________ m. 2. The freezing point of the solution is __________ °C. **Explanation of the Table:** The table provides the boiling point elevation constants (\( K_b \)) and freezing point depression constants (\( K_f \)) for various solvents. - **Water (H₂O):** has a \( K_b \) of 0.512°C/m and a \( K_f \) of 1.86°C/m. - **Ethanol (CH₃CH₂OH):** has a \( K_b \) of 1.22°C/m and a \( K_f \) of 1.99°C/m. - **Chloroform (CHCl₃):** only provides a \( K_b \) of 3.67°C/m. - **Benzene (C₆H₆):** has a \( K_b \) of 2.53°C/m and a \( K_f \) of 5.12°C/m. - **Diethyl ether (CH₃CH₂OCH₂CH₃):** only provides a \( K_b \) of 2.02°C/m. These constants
Expert Solution
Step 1

Given 

Mass of Sodium acetate =  12.27 gram 

Molar mass of sodium acetate =  82 gram/mole

Mass of water = 174.4 gram

                       = 0.1744 Kg                   ( 1 gram = 10-3 Kg ) 

Freezing point of water = 0 ℃ 

Molality of solution = ? 

Freezing point of solution = ?

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