Calculate the formula of FeCl3 NH2O if you started with 8.99 g of iron (III) chloride hydrate. After heating, the mass was reduced to 4.5 g of anhydrous iron (III) chloride.
Basics in Organic Reactions Mechanisms
In organic chemistry, the mechanism of an organic reaction is defined as a complete step-by-step explanation of how a reaction of organic compounds happens. A completely detailed mechanism would relate the first structure of the reactants with the last structure of the products and would represent changes in structure and energy all through the reaction step.
Heterolytic Bond Breaking
Heterolytic bond breaking is also known as heterolysis or heterolytic fission or ionic fission. It is defined as breaking of a covalent bond between two different atoms in which one atom gains both of the shared pair of electrons. The atom that gains both electrons is more electronegative than the other atom in covalent bond. The energy needed for heterolytic fission is called as heterolytic bond dissociation energy.
Polar Aprotic Solvent
Solvents that are chemically polar in nature and are not capable of hydrogen bonding (implying that a hydrogen atom directly linked with an electronegative atom is not found) are referred to as polar aprotic solvents. Some commonly used polar aprotic solvents are acetone, DMF, acetonitrile, DMSO, etc.
Oxygen Nucleophiles
Oxygen being an electron rich species with a lone pair electron, can act as a good nucleophile. Typically, oxygen nucleophiles can be found in these compounds- water, hydroxides and alcohols.
Carbon Nucleophiles
We are aware that carbon belongs to group IV and hence does not possess any lone pair of electrons. Implying that neutral carbon is not a nucleophile then how is carbon going to be nucleophilic? The answer to this is that when a carbon atom is attached to a metal (can be seen in the case of organometallic compounds), the metal atom develops a partial positive charge and carbon develops a partial negative charge, hence making carbon nucleophilic.
With the information provided answer #2
![**Title: Analysis of a Hydrate**
**Description:**
This image captures a scientific board illustrating the chemical analysis of a hydrate. It depicts a general chemical reaction:
\[ \text{CuSO}_4 \cdot \text{x H}_2\text{O} \rightarrow \text{CuSO}_4(s) + \text{x H}_2\text{O}(g) \]
**Explanation:**
- **Reaction Components:**
- \( \text{CuSO}_4 \cdot \text{x H}_2\text{O} \) represents a hydrate of copper sulfate, where \( x \) indicates the number of water molecules associated with each formula unit of copper sulfate.
- \( \text{CuSO}_4(s) \) is the anhydrous (water-free) form of copper sulfate.
- \( \text{x H}_2\text{O}(g) \) denotes the water molecules released as a gas upon heating.
- **Process:**
- When hydrated copper sulfate is heated, it loses water and transforms into an anhydrous form, illustrating the dehydration process common in chemical compounds.
- The formula \( \text{CuSO}_4 \cdot \text{x H}_2\text{O} \) emphasizes the stoichiometric ratio of water to the copper sulfate, which is key to understanding the properties and behavior of hydrates in chemical reactions.
This reaction embodies critical concepts such as stoichiometry, phase changes, and chemical transformations within the study of chemistry. Understanding these principles is essential for various applications, including laboratory experiments and industrial processes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7cb7ab84-2909-44b4-aa38-afda86b9d9a5%2F51ca49a6-23bf-4048-ae7d-0621f098105e%2Fgaarhoo.jpeg&w=3840&q=75)
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