edThe boiling point of water is 100.00 °C at 1 atmosphere.A student dissolves 12.63 grams of sodium sulfide, Na₂S (78.05 g/mol), in 163.3 grams of water. Use the table ofboiling and freezing point constants to answer the questions below.SolventWaterEthanolChloroformBenzeneFormulaH₂OCH3CH₂OHCHCI 3соноDiethyl ether CH3CH₂CH₂CH3The molality of the solution isThe boiling point of the solution isKb (°C/m) Kf (°C/m)0.5121.861.221.993.672.532.02m.°C.5.12

Answered: Image /qna-images/answer/5ef6e90c-bd16-4a41-9faa-5a6b67c6d3d4.jpg

tudent dissolves 12.63 grams of sodium sulfide, Na₂S (78.05 g/mol), in 163.3 gram ing and freezing point constants to answer the questions below. Formula H₂O CH3CH₂OH CHCI 3 C6H6 Diethyl ether CH3CH₂CH₂CH3 Solvent Water Ethanol Chloroform Benzene molality of the solution is Kb (°C/m) Kf (°C/m) 0.512 1.86 1.22 1.99 3.67 2.53 2.02 m. 5.12

tudent dissolves 12.63 grams of sodium sulfide, Na₂S (78.05 g/mol), in 163.3 gram ing and freezing point constants to answer the questions below. Formula H₂O CH3CH₂OH CHCI 3 C6H6 Diethyl ether CH3CH₂CH₂CH3 Solvent Water Ethanol Chloroform Benzene molality of the solution is Kb (°C/m) Kf (°C/m) 0.512 1.86 1.22 1.99 3.67 2.53 2.02 m. 5.12

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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