The boiling point of ethanol CH3CH,OH is 78.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in ethanol is testosterone. How many grams of testosterone, C19H2302 (288.4 g/mol), must be dissolved in 224.0 grams of ethanol to raise the boiling point by 0.300 °C ? Refer to the table for the necessary boiling or freezing point constant.

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The boiling point of ethanol CH3CH,OH is 78.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in ethanol is
testosterone.
How many grams of testosterone, C1,H2802 (288.4 g/mol), must be dissolved in 224.0 grams of ethanol to raise the boiling point by
0.300 °C ? Refer to the table for the necessary boiling or freezing point constant.
Formula
| K, (°C/m) Kf(°C/m)
Solvent
Water
H,0
0.512
1.86
Ethanol
CH;CH,OH
1.22
1.99
Chloroform
CHC13
3.67
Benzene
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
g testosterone.
Transcribed Image Text:The boiling point of ethanol CH3CH,OH is 78.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in ethanol is testosterone. How many grams of testosterone, C1,H2802 (288.4 g/mol), must be dissolved in 224.0 grams of ethanol to raise the boiling point by 0.300 °C ? Refer to the table for the necessary boiling or freezing point constant. Formula | K, (°C/m) Kf(°C/m) Solvent Water H,0 0.512 1.86 Ethanol CH;CH,OH 1.22 1.99 Chloroform CHC13 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH2OCH2CH3 2.02 g testosterone.
Expert Solution
Given

Number of grams of ethanol given = 224.0 g

Molar mass of testosterone = 288.4 g/mol

Elevation in boiling point required, Tb = 0.300 oC

Elevation in boiling point constant for ethanol, Kb = 1.22 oC/m

 

Elevation in boiling point and calculation of molality

According to the colligative property of elevation in boiling point -

Tb =Kb·m

where, m = molality of the solution

Tb =Kb·mm =Tb Kbm =0.300 °C1.22 °C/mMolality, m =0.246 m = 0.246 mol/Kg

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