The framing plan of a two-storey reinforced concrete structure is shown below. Due to some issues, the owner suggests to change the corner columns to equivalent circular columns of the same section modulus as the initial square columns designated as shown in the figure. Compute the factors for the distribution of lateral forces per frame. The size of the square columns is 0.50 by 0.50m, girders are 0.3 x 0.5m. Height per level is 3.60 meters. E = 24.84 x 10^6 kPa and G = 9.92 x 10^6 kPA. Use column A-1 as building reference point. Weight at the second level is 1345.23 kN and that of the deck level is 1103.25 kN. The seismic data are as follows: Cv = 0.32Nv, Nv = 1.2, I = 1.0, R=8.5, Ca = 0.32Na, Na = 1.0, Z=0.4. Use 6 decimal places. Analyze frame 1 using Factor Method. Accidental eccentricity is 5% of the total transverse dimension of the structure (24.3m). Use 6 decimal places. Determine the lateral force in the 2nd level (vertical distribution).
The framing plan of a two-storey reinforced concrete structure is shown below. Due to some issues, the owner suggests to change the corner columns to equivalent circular columns of the same section modulus as the initial square columns designated as shown in the figure. Compute the factors for the distribution of lateral forces per frame. The size of the square columns is 0.50 by 0.50m, girders are 0.3 x 0.5m. Height per level is 3.60 meters. E = 24.84 x 10^6 kPa and G = 9.92 x 10^6 kPA. Use column A-1 as building reference point. Weight at the second level is 1345.23 kN and that of the deck level is 1103.25 kN. The seismic data are as follows: Cv = 0.32Nv, Nv = 1.2, I = 1.0, R=8.5, Ca = 0.32Na, Na = 1.0, Z=0.4. Use 6 decimal places. Analyze frame 1 using Factor Method. Accidental eccentricity is 5% of the total transverse dimension of the structure (24.3m). Use 6 decimal places. Determine the lateral force in the 2nd level (vertical distribution).
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The framing plan of a two-storey reinforced concrete structure is shown below. Due to some issues, the owner suggests to change the corner columns to equivalent circular columns of the same section modulus as the initial square columns designated as shown in the figure. Compute the factors for the distribution of lateral forces per frame. The size of the square columns is 0.50 by 0.50m, girders are 0.3 x 0.5m. Height per level is 3.60 meters. E = 24.84 x 10^6 kPa and G = 9.92 x 10^6 kPA. Use column A-1 as building reference point. Weight at the second level is 1345.23 kN and that of the deck level is 1103.25 kN. The seismic data are as follows: Cv = 0.32Nv, Nv = 1.2, I = 1.0, R=8.5, Ca = 0.32Na, Na = 1.0, Z=0.4. Use 6 decimal places. Analyze frame 1 using Factor Method. Accidental eccentricity is 5% of the total transverse dimension of the structure (24.3m). Use 6 decimal places.
Determine the lateral force in the 2nd level (vertical distribution).
Transcribed Image Text:A
B
8.80m
8.20m
10.80m
(1)
8.10m
2
8.10m
3
8.10m
4
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