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section of the column and the interaction diagram are shown below. Determine the total area of longitudinal reinforcement needed to resist the applied loads. fc = 5000 psi, fy = 60000 psi 20 zh b=12" 1.0 f'.s4,000 psi fy = 60,000 psi Y = 0.75 0.9 0.8 e/h = 0,1 0.7 A0.03 e/h=0.2 0.6 =D.02 Ps=0.01 e/h = 0,3 0.5 e/h = 0,4 0.4 e/h = 0.5 0.3 e/h =0.6 e/h 0.7 0.2 e/h= 10 e/h= 15 0.1 0.0 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0.20 0.22 0.24 M,/(f'Agh)

section of the column and the interaction diagram are shown below. Determine the total area of longitudinal reinforcement needed to resist the applied loads. fc = 5000 psi, fy = 60000 psi 20 zh b=12" 1.0 f'.s4,000 psi fy = 60,000 psi Y = 0.75 0.9 0.8 e/h = 0,1 0.7 A0.03 e/h=0.2 0.6 =D.02 Ps=0.01 e/h = 0,3 0.5 e/h = 0,4 0.4 e/h = 0.5 0.3 e/h =0.6 e/h 0.7 0.2 e/h= 10 e/h= 15 0.1 0.0 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0.20 0.22 0.24 M,/(f'Agh)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A reinforced concrete column is subjected to the following service axial loads and moments: PD =100 kips, PL=129 kips; Mp = 60 kip-ft and ML = 92.5 kip-ft. The cross 3
Transcribed Image Text:A reinforced concrete column is subjected to the following service axial loads and moments: PD =100 kips, PL=129 kips; Mp = 60 kip-ft and ML = 92.5 kip-ft. The cross 3
section of the column and the interaction diagram are shown below. Determine the total area of longitudinal reinforcement needed to resist the applied loads. fc = 5000 psi, Iy = 60000 psi 20 zh b=12" 1.0 f'.s4,000 psi fy = 60,000 psi Y = 0.75 0.9 0.8 e/h = 0,1 0.7 Pa0.03 Le/h=0.2 0.6 =0.02 Ps=0.01 e/h = 0,3 0.5 e/h = 0,4 0.4 e/h =0.5 0.3 e/h = 0.6 Le/h=0.7 0.2 e/h = 10 e/h= 15 0.1 0.0 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0.20 0.22 0.24 M,/(f'Agh)
Transcribed Image Text:section of the column and the interaction diagram are shown below. Determine the total area of longitudinal reinforcement needed to resist the applied loads. fc = 5000 psi, Iy = 60000 psi 20 zh b=12" 1.0 f'.s4,000 psi fy = 60,000 psi Y = 0.75 0.9 0.8 e/h = 0,1 0.7 Pa0.03 Le/h=0.2 0.6 =0.02 Ps=0.01 e/h = 0,3 0.5 e/h = 0,4 0.4 e/h =0.5 0.3 e/h = 0.6 Le/h=0.7 0.2 e/h = 10 e/h= 15 0.1 0.0 0.00 0.02 0.04 0.06 0.08 0.10 0.12 0.14 0.16 0.18 0.20 0.22 0.24 M,/(f'Agh)
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