The following initial rate data are for the reaction of tertiary butyl bromide with hydroxide ion at 55 °C: (CH3)3CB + OH (CH)3COН + Br Experiment [(CH3)3CB1],. M [OH], M Initial Rate, Ms1 6.64x10-3 6.64x10-3 1.33x10-2 1.33x10-2 1 0.540 0.408 0.540 0.816 1.08 0.408 1.08 0.816 Complete the rate law for this reaction in the box below. Use the form k[A]"[B]" , where 'l' is understood for m or n and concentrations taken to the zero power do not appear. Don't enter 1 for m or n Rate = From these data, the rate constant is

The following initial rate data are for the reaction of tertiary butyl bromide with hydroxide ion at 55 °C: (CH3)3CB + OH (CH)3COН + Br Experiment [(CH3)3CB1],. M [OH], M Initial Rate, Ms1 6.64x10-3 6.64x10-3 1.33x10-2 1.33x10-2 1 0.540 0.408 0.540 0.816 1.08 0.408 1.08 0.816 Complete the rate law for this reaction in the box below. Use the form k[A]"[B]" , where 'l' is understood for m or n and concentrations taken to the zero power do not appear. Don't enter 1 for m or n Rate = From these data, the rate constant is

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

5. answer choices are a none of these d a c
None
Please solve this problem
plz answer in handwritten
Please ? thank you ?
Please describe what would happen to the rate if given changes were applied to following reactions: Ex.: Doubling the concentration of both KOH and starting material in the reaction below Br OH KOH It is a 2nd order reaction. Doubling the concentration of both will result in 4x the speed of the reaction. DMF 1. Doubling the concentration of starting material and alcohol in the reaction below Br Br CH3OH 2. Using half of the alcohol in the reaction shown below CH3OK CH3OH
4. Explain why the rate of formation of 1-azidopropane is different depending on which halopropane (X = F, Cl, Br, I) is used. Explain which halopropane will react fastest? ~X X = F, Cl, Br, I NaN №3 1-azidopropane
In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2 H* + 21 -1, + 2 H,0 (1) with the following proposed three-step reaction mechanism: Step 1: (slow) H,O, +1 - OH" + HOI Step 2: (very fast) OH + H* - H,0 Step 3: (fast) HOI + H* + 12 + H20 In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + 0,(g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H,O, +1 - OH + HOI Step 2a: (very fast) OH + HOI - 10 + H,0 H,0, + 10 -I + H20 + 0,(g) 2 H0 2 H0 t OI Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast)
12:10 1 Question 22 of 25 Submit Which species has the greatest rate of disappearance in the reaction below? CH4 + 2 O2 → 2 CO2 + H20 A) CH4 B) O2 C) СО2 D) H;O E) CH, and O, have identical rates
Please answer all parts
Explain your reasoning, please. Thank you.
number 5:answer only letter D thanks