In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,0, - 2 H,0 + O;{g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H,O, +1 - OH + HOI Step 2a: (very fast) OH + HOI - 10- + H,0 H,0 + 10 I + H,0 + 0;(g) 2 H202 → 2 HzO + OLCJ Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast) What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is limited by the slow Step 1?

Chemistry
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Chapter1: Chemical Foundations
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In this experiment you studied the following net chemical reaction that we will call reaction (1):
H,0, + 2H + 21 - 1, + 2 H,0
(1)
with the following proposed three-step reaction mechanism:
H,0, +1 - OH + HOI
OH + H* - H,0
HOI + H* + - l + H,0
Step 1: (slow)
Step 2: (very fast)
Step 3: (fast)
In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction
occurs:
2 H,02 - 2 H,0 + 0,{g)
(2)
The following three-step reaction mechanism has been proposed to explain reaction (2):
Step 1: (slow)
H,0, +1 - OH + HOI
Step 2a: (very fast) OH + HOI 10 + H,0
H,0, + 10I + H20 + 0,(g)
2 H202 → 2 HzO + OeC5)
Show that when you sum the three reaction steps the net result is reaction (2):
Step 3a: (fast)
What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is
limited by the slow Step 1?
Transcribed Image Text:In this experiment you studied the following net chemical reaction that we will call reaction (1): H,0, + 2H + 21 - 1, + 2 H,0 (1) with the following proposed three-step reaction mechanism: H,0, +1 - OH + HOI OH + H* - H,0 HOI + H* + - l + H,0 Step 1: (slow) Step 2: (very fast) Step 3: (fast) In neutral solution containing only hydrogen peroxide and iodide ion, a different net chemical reaction occurs: 2 H,02 - 2 H,0 + 0,{g) (2) The following three-step reaction mechanism has been proposed to explain reaction (2): Step 1: (slow) H,0, +1 - OH + HOI Step 2a: (very fast) OH + HOI 10 + H,0 H,0, + 10I + H20 + 0,(g) 2 H202 → 2 HzO + OeC5) Show that when you sum the three reaction steps the net result is reaction (2): Step 3a: (fast) What would be the expected rate law for the reaction mechanism, assuming that the rate of reaction (2) is limited by the slow Step 1?
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