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- The data in NutritionStudy include information on nutrition and health habits of a sample of 315 people. One of the variables is VitaminUse, indicating whether a person takes a multivitamin pill regularly or occasionally or not at all. Use technology to test whether the data provide evidence that the proportion taking a vitamin pill regularly is different from 35 % given. Clearly state the null and alternative hypotheses. : : 42 : Pi : P2 :: 0.35 : 2 :: P1 : p2 :: :: r Ho: vs Hg: ::H0 : =150.00 kPa H1 :>150.00 kPa b) α= 0.01; sample variance : 1300 freq. table sample deviation : 36.0555 freq. tableThe concentration of carbon monoxide (CO) in a gas sample is measured by a spectrophotometer and found to be 85 ppm. Through long experience with this instrument, it is believed that its measurements are unbiased and normally distributed, with an uncertainty (standard deviation) of 8 ppm. Find a 95% confidence interval for the concentration of CO in this sample.
- Table 1: A random sampling of 30 homes in the Winston-Salem area. Price Size (single- or multi-level) 178,900 1 218,000 239,900 1 142,000 1 183,200 279,600 199,900 2 2 314,900 130,000 2 339,900 200,000 254,900 293,500 1 2 1 2 225,000 2 249,900 2 145,000 1 284,900 259,900 1 1 165,000 277,900 210,000 1 2 285,000 174,900 195,000 1 289,900 2 225,000 2 179,000 248,900 1 2 209,900 2 225,000Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of μ=8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of x=7.3 ppb arsenic. It is known that σ=1.9 ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use α=0.01 What is the hypotheses for this problem? A: Ho μ =7.3ppb vs HA μ < 7.3ppb B: Ho μ <7.3ppb vs HA μ ≥ 7.3ppb C: Ho μ =8.0ppb vs HA μ < 8.0ppb D: Ho μ <8.0ppb vs HA μ ≥ 8.0ppbThe tensile strength of paper using 5% hardwood and 10% hardwood are to be compared. A random sample of 41 sheets made from 5% hardwood had an average tensile strength of 1.52 lbs. with a standard deviation of 0.33 lbs. A random sample of 61 sheets made from 10% hardwood had an average tensile strength of 1.88 lbs. with a standard deviation of 0.42 lbs. Can we conclude the average tensile strength is the same for the two types of paper? Use 5% significance and p-values. Part 1) Conduct the test using the assumption that the sample standard deviations are the same as the population standard deviations. Part 2) Conduct the test using the assumption that the population standard deviations are unknown but equal (you also must assume a normal population here). Part 3) Conduct the test with only the assumption that we have simple random samples from normal populations. May you please explain which stat test you used on your calculator and why. Thank you very much for your help!
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- Type I error: Washers used in a certain application are supposed to have a thickness of 2 millimeters. A quality control engineer measures the thicknesses for a sample of washers and tests H0: μ = 2 versus H1: μ ≠ 2. a. If a Type I error is made, what conclusion will be drawn regarding the mean washer thickness?Which of the following would probably NOT be a potential “cure” for non-normal residuals? Select one: a. Transforming two explanatory variables into a ratio. b. Removing large negative residuals. c. Removing large positive residuals. d. Using a procedure for estimation and inference which did not assume normality.Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.4 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use a = 0.05.) State the appropriate hypotheses. O H,: H 48 H:u = 48 O H,: = 48 Hi u 48 OH:= 48 H: u + 48 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to three decimal places.) P-value = What can you conclude? O The data provides compelling…