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According to a study, the median time a patient waits to see a doctor in an emergency room is 30 minutes. Consider an emergency room on a day when 200 patients visit. a. What is the probability that more than half will wait more than 30 minutes? b. What is the probability that more than 105 will wait more than 30 minutes? c. What is the probability that more than 85 but less than 115 will wait more than 30 minutes? a. The probability is 0.472. (Round to three decimal places as needed.) b. The probability is 0.218. (Round to three decimal places as needed.) c. The probability is (Round to three decimal places as needed.) Calculate the interval shown below, where μ is the mean, σ is the standard deviation, n is the number of trials, p is the probability of success on a single trial, and q is 1 - p. If the interval lies in the range 0 to n, the normal distribution will provide a reasonable approximation to the probabilities of most binomial events. μ ± 3σ = np± 3√/pq If the normal distribution provides a reasonable approximation, express the binomial probability to be approximated in the form P(x≤a). For the value of interest, a, the correction for continuity is (a + .5). The corresponding standard normal z-value is shown below. Z= (a+.5)-μ Use this z-value and either technology or a table of normal curve areas to find P(x≤a) for both the upper and lower values, and then subtract the lower value from the upper value to find the area between these two values.

According to a study, the median time a patient waits to see a doctor in an emergency room is 30 minutes. Consider an emergency room on a day when 200 patients visit. a. What is the probability that more than half will wait more than 30 minutes? b. What is the probability that more than 105 will wait more than 30 minutes? c. What is the probability that more than 85 but less than 115 will wait more than 30 minutes? a. The probability is 0.472. (Round to three decimal places as needed.) b. The probability is 0.218. (Round to three decimal places as needed.) c. The probability is (Round to three decimal places as needed.) Calculate the interval shown below, where μ is the mean, σ is the standard deviation, n is the number of trials, p is the probability of success on a single trial, and q is 1 - p. If the interval lies in the range 0 to n, the normal distribution will provide a reasonable approximation to the probabilities of most binomial events. μ ± 3σ = np± 3√/pq If the normal distribution provides a reasonable approximation, express the binomial probability to be approximated in the form P(x≤a). For the value of interest, a, the correction for continuity is (a + .5). The corresponding standard normal z-value is shown below. Z= (a+.5)-μ Use this z-value and either technology or a table of normal curve areas to find P(x≤a) for both the upper and lower values, and then subtract the lower value from the upper value to find the area between these two values.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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c. What is the probability that more than 85 but less than 115 will wait more than 30​ minutes? Please help solve this question. Use the information from the image attached.
According to a study, the median time a patient waits to see a doctor in an emergency room is 30 minutes. Consider an emergency room on a day when 200 patients visit. a. What is the probability that more than half will wait more than 30 minutes? b. What is the probability that more than 105 will wait more than 30 minutes? c. What is the probability that more than 85 but less than 115 will wait more than 30 minutes? a. The probability is 0.472. (Round to three decimal places as needed.) b. The probability is 0.218. (Round to three decimal places as needed.) c. The probability is (Round to three decimal places as needed.)
Transcribed Image Text:According to a study, the median time a patient waits to see a doctor in an emergency room is 30 minutes. Consider an emergency room on a day when 200 patients visit. a. What is the probability that more than half will wait more than 30 minutes? b. What is the probability that more than 105 will wait more than 30 minutes? c. What is the probability that more than 85 but less than 115 will wait more than 30 minutes? a. The probability is 0.472. (Round to three decimal places as needed.) b. The probability is 0.218. (Round to three decimal places as needed.) c. The probability is (Round to three decimal places as needed.)
Calculate the interval shown below, where μ is the mean, σ is the standard deviation, n is the number of trials, p is the probability of success on a single trial, and q is 1 - p. If the interval lies in the range 0 to n, the normal distribution will provide a reasonable approximation to the probabilities of most binomial events. μ ± 3σ = np± 3√/pq If the normal distribution provides a reasonable approximation, express the binomial probability to be approximated in the form P(x≤a). For the value of interest, a, the correction for continuity is (a + .5). The corresponding standard normal z-value is shown below. Z= (a+.5)-μ Use this z-value and either technology or a table of normal curve areas to find P(x≤a) for both the upper and lower values, and then subtract the lower value from the upper value to find the area between these two values.
Transcribed Image Text:Calculate the interval shown below, where μ is the mean, σ is the standard deviation, n is the number of trials, p is the probability of success on a single trial, and q is 1 - p. If the interval lies in the range 0 to n, the normal distribution will provide a reasonable approximation to the probabilities of most binomial events. μ ± 3σ = np± 3√/pq If the normal distribution provides a reasonable approximation, express the binomial probability to be approximated in the form P(x≤a). For the value of interest, a, the correction for continuity is (a + .5). The corresponding standard normal z-value is shown below. Z= (a+.5)-μ Use this z-value and either technology or a table of normal curve areas to find P(x≤a) for both the upper and lower values, and then subtract the lower value from the upper value to find the area between these two values.
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