Amber is an archeologist and is trying to date some furniture that was made of wood. Other experts put the date of the site at 1119 ce, but she thinks it is much earlier than that and wishes to perform her test a an alpha level of 0.01. Consider the following Conclusion and Confidence Interval statement: Conclusion: Amber collected sufficient evidence to reject the claim that the true proportion is 1119 and conclude that the true population proportion is greater than 1119. There are several issues with this statement. Select the problems applicable here:
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- The recidivism rate for convicted sex offenders is 9%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 396 convicted sex offenders who were also drug addicts, 51 of them became repeat offenders. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Но: 0.09 |(please enter a decimal) H1: P 0.09 (Please enter a decimal) c. The test statistic ? 2.697 (please show your answer to 3 decimal places.) d. The p-value =| 0.0035 v (Please show your answer to 4 decimal places.) e. The p-value is f. Based on this, we should reject the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton proportion is significantly higher than 9% at a = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat…The recidivism rate for convicted sex offenders is 9%. A warden suspects that this percent is higher if the sex offender is also a drug addict. Of the 396 convicted sex offenders who were also drug addicts, 51 of them became repeat offenders. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Но: р 0.09 (please enter a decimal) H1: P 0.09 V (Please enter a decimal) c. The test statistic ? V = 2.697 (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the populaton proportion is significantly higher than 9% at a = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become…According to a University Center for Logistics Management, 8% of all merchandise sold in the United States gets returned. Seattle department store sampled 88 items sold in January and found that 8 of the items were returned. If you have the following null and alternative hypotheses for a test you are running: Ho:p = 0.08 Ha:p < 0.08 Calculate the test statistic, rounded to 3 decimal places. Submit Question Ce %23 24 % 4. 7 80 e r u SI d b. 60 65
- Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 79 bpm. Use a 0.05 significance level. LOADING... Click the icon to view the pulse rate data. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? A. H0: μ=79 bpm H1: μ≠79 bpm B. H0: μ>79 bpm H1: μ<79 bpm C. H0: μ=79 bpm H1: μ<79 bpm D. H0: μ=79 bpm H1: μ>79 bpm Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Reject Fail to reject H0. There is ▼ not sufficient sufficient evidence to conclude that the mean of the population of pulse rates for adult females is ▼ greater than not less than…We want to determine if the true proportion of students who do aerobics is less than 45%. Which are the correct hypotheses? Ho: P = 0.45; Ha: P≠ 0.45 Ho: P = 0.45; Ha: P > 0.45 Ho: P ≥ 0.45; Ha:P < 0.45 Ho: μ ≥ 0.45; Ha: μ < 0.45Next Question Assume a significance level of a = 0.05 and use the given information to cd d (b) below. Original claim: More than 43% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.0443. ..... a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. A. Fail to reject Ho because the P-value is greater than x. B. Reject H, because the P-value is less than or equal to a. C. Fail to reject H, because the P-value is less than or equal to a. O D. Reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 43%. B. There is not sufficient evidence to support the…
- Hunter is writing a report on the backgrounds of American presidents. He finds that the mean age of the 45 presidents is 55 years with the standard deviation of 6.59 years. Because Hunter took a statistics course, he calculates a 95% confidence interval for the mean age of all men who have been president to be 55 ± 1.98. Comment on this result. Question 8 options: Hunter can be 95% confident that the mean age of all presidents is 55 years. 95% of all the ages of the presidents lie between 55 ± 1.98. Hunter should have taken a larger sample to reduce the margin of error. Hunter is 95% confident that the mean age of all presidents lies between 53.02 and 56.98 years. The confidence interval makes no sense since Hunter has the entire population of ages.Only about 17% of all people can wiggle their ears. Is this percent higher for millionaires? Of the 381 millionaires surveyed, 80 could wiggle their ears. What can be concluded at the a= 0.05 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Ho: P .17 (please enter a decimal) H₁: (p .17 (Please enter a decimal) c. The test statistic (z) 0.208 X (please show your answer to 3 decimal places.) d. The p-value = 0.418 X (Please show your answer to 3 decimal places.) e. The p-value is (s) a f. Based on this, we should (reject the null hypothesis.A random sample of size 16 from a normal distribution has standard aviation s = 74. Test H: o=32 VersUs H: o> 32. Use the a=0.01 level of significance.
- Approximately 10%10% of Americans are left-handed (we will treat this as a known population parameter). A study on the relationship between handedness and profession found that in a random sample of 105 lawyers, 16 of them were left-handed.1 Test the hypothesis that the proportion of left-handed lawyers differs from the proportion of left-handed Americans. Clearly state the null and alternative hypotheses.Let pp be the proportion of left-handed lawyers. Calculate the test statistic and p-value.Round your answer for the test statistic to two decimal places, and your answer for the p-value to three decimal places.test statistic = Enter your answer; test statisticp-value = Enter your answer; p-value What do we conclude at the 5% significance level? At the 10% significance level? Significance Level Conclusion 5% Choose the answer from the menu; What do we conclude at the 5% significance level?…Answer the last questionTourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May 19, 2018). Hotel occupancy data for February in two consecutive years are as follows. Occupied Rooms Total Rooms Current Year Let pi population proportion of rooms occupied for current year P = population proportion of rooms occupied for previous year 1,435 1,750 Previous Year a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Ho Pi-Pa-Select your answer- H.: P-P-Select your answer- b. What is the estimated proportion of hotel rooms occupied each year (to 2 decimals)? 1,404 1,800 Current year Previous Year c. Conduct a hypothesis test. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. p-value- Using a 0.05 level of significance, what is your conclusion? We Select your answer that there has been an…