The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl). Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol NaHCO3 and 8 mol HCl.
The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl).
Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol NaHCO3 and 8 mol HCl.
Given,
one mole of sodium bicarbonate (NaHCO3) reacting with one mole of hydrochloric acid (HCl) to produce one mole of carbonic acid (H2CO3), and one mole of sodium chloride (NaCl).
Writing the balanced chemical equation,
NaHCO3 + HCl → NaCl + H2CO3
moles of NaHCO3 reacts = 5 mol
moles of HCl reacts = 8 mol
moles of carbonic acid (H2CO3) produced = ?
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