Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CHĄ(9)+2H,S(g) –→ 4H,(9)+CS,(g) Use this chemical equation to answer the questions in the table below. Suppose 235. mmol of CH, and None. 470. mmol of H,S are added to an O Some, but less than 940. mmol. empty flask. How much H, will be in O 940. mmol. the flask at equilibrium? O More than 940. mmol. Suppose 75.0 mmol of H, and O None. 18.8 mmol of CS, are added to an O Some, but less than 75.0 mmol. empty flask. How much H, will be in O 75.0 mmol. the flask at equilibrium? O More than 75.0 mmol.
Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this: CHĄ(9)+2H,S(g) –→ 4H,(9)+CS,(g) Use this chemical equation to answer the questions in the table below. Suppose 235. mmol of CH, and None. 470. mmol of H,S are added to an O Some, but less than 940. mmol. empty flask. How much H, will be in O 940. mmol. the flask at equilibrium? O More than 940. mmol. Suppose 75.0 mmol of H, and O None. 18.8 mmol of CS, are added to an O Some, but less than 75.0 mmol. empty flask. How much H, will be in O 75.0 mmol. the flask at equilibrium? O More than 75.0 mmol.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this:
CH4(g)+2H2S(g)→4H2(g)+CS2(g)
Use this chemical equation to answer the questions in the table below.
Transcribed Image Text:Methane and hydrogen sulfide react to form hydrogen and carbon disulfide, like this:
CHĄ(9)+2H,S(g) –→ 4H,(9)+CS,(g)
Use this chemical equation to answer the questions in the table below.
Suppose 235. mmol of CH, and
None.
470. mmol of H,S are added to an
O Some, but less than 940. mmol.
empty flask. How much H, will be in
O 940. mmol.
the flask at equilibrium?
O More than 940. mmol.
Suppose 75.0 mmol of H, and
O None.
18.8 mmol of CS, are added to an
O Some, but less than 75.0 mmol.
empty flask. How much H, will be in
O 75.0 mmol.
the flask at equilibrium?
O More than 75.0 mmol.
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