Ethylene and chlorine react to form ethylene dichloride, like this: CH₂CH₂(g) + Cl₂(g) → CH₂CH₂Cl₂(g) Use this chemical equation to answer the questions in the table below. Suppose 55.0 mmol of CH₂CH₂ and 55.0 mmol of Cl₂ are added to an empty flask. How much CH₂CH₂ will be in the flask at equilibrium? Suppose 120. mmol of CH₂CH₂Cl₂ are added to an empty flask. How much CH₂CH₂ will be in the flask at equilibrium? None. O Some, but less than 55.0 mmol. ○ 55.0 mmol. O More than 55.0 mmol. None. O Some, but less than 120. mmol. O 120. mmol. O More than 120. mmol. X

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Ethylene and chlorine react to form ethylene dichloride, like this:
CH₂CH₂(g) + Cl₂(g) → CH₂CH₂Cl₂(g)
Use this chemical equation to answer the questions in the table below.
Suppose 55.0 mmol of CH₂CH₂ and
55.0 mmol of Cl₂ are added to an
empty flask. How much CH₂CH₂
will be in the flask at equilibrium?
Suppose 120. mmol of CH₂CH₂Cl2
are added to an empty flask. How
much CH₂CH₂ will be in the flask at
equilibrium?
None.
Some, but less than 55.0 mmol.
55.0 mmol.
More than 55.0 mmol.
None.
Some, but less than 120. mmol.
O 120. mmol.
O More than 120. mmol.
00000
Transcribed Image Text:Ethylene and chlorine react to form ethylene dichloride, like this: CH₂CH₂(g) + Cl₂(g) → CH₂CH₂Cl₂(g) Use this chemical equation to answer the questions in the table below. Suppose 55.0 mmol of CH₂CH₂ and 55.0 mmol of Cl₂ are added to an empty flask. How much CH₂CH₂ will be in the flask at equilibrium? Suppose 120. mmol of CH₂CH₂Cl2 are added to an empty flask. How much CH₂CH₂ will be in the flask at equilibrium? None. Some, but less than 55.0 mmol. 55.0 mmol. More than 55.0 mmol. None. Some, but less than 120. mmol. O 120. mmol. O More than 120. mmol. 00000
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