In the reaction of 10.00 mL of FeCl3(aq) and 12.4 g ofK2C204(ag), you calculate that 9.58 g of K3FEC2043H2O(s)will be produced. What does 9.58 g represent?percent yieldlimiting reactantactual yieldmolar masstheoretical yield

Volume of FeCl3 = 10.00 mL Mass of K2C2O4 : 12.4 g Mass of K3FeC2O43H2O = 9.58 g

n the reaction of 10.00 mL of FeCl3{aq) and 12.4 g of <½C2O4laq). you calculate that 9.58 g of K3FEC2O43H20 will be produced. What does 9.58 g represent? percent yield O limiting reactant O actual yield molar mass O theoretical yield

n the reaction of 10.00 mL of FeCl3{aq) and 12.4 g of <½C2O4laq). you calculate that 9.58 g of K3FEC2O43H20 will be produced. What does 9.58 g represent? percent yield O limiting reactant O actual yield molar mass O theoretical yield

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 30A

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