The figure depicts a simplistic optical fiber: a plastic core (n, = 1.56) is surrounded by a plastic sheath (n2 = 1.44). A light ray is incident on one end of the fiber at angle 0. The rays is to undergo total internal reflection at point A, where it encounters the core-sheath boundary. (Thus there is no loss of light through that boundary.) What is the maximum value of e that allows total internal reflection at A? Number Units
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- The figure shows an optical fiber in which a central plastic core of index of refraction n1 = 1.60 is surrounded by a plastic sheath of index of refraction n2 = 1.52. Light can travel along different paths within the central core, leading to different travel times through the fiber. This causes an initially short pulse of light to spread as it travels along the fiber, resulting in information loss. Consider light that travels directly along the central axis of the fiber and light that is repeatedly reflected at the critical angle along the core-sheath interface, reflecting from side to side as it travels down the central core. If the fiber length is 370 m, what is the difference in the travel times along these two routes? NUmber i 99 Units nsA light ray enters a rectangular block of plastic at an angle 0, = 47.8° and emerges at an angle 0, = 73.2°, as shown in the figure below. (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, how long does it take the light ray to travel through the plastic? nsFor the optical fiber shown in the figure, find the minimum angle of incidence (0;) that will result in total internal reflection if the refractive index for the cladding (n2) is 1.46 and the refractive index of the core is (A.) n1 = 1.51 and (B.) nị = 1.76. Cone of acceptance п, Core Cladding (n,) А. B.
- Light rays in a material with index of refrection 1.39 can undergo total internal reflection when they strike the interface with another material at a critical angle of incidence. Find the second material's index of refraction n when the required critical angle is 73.3°. n =A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.520 and is submerged in ethyl alcohol, which has an index of refraction of 1.361. What is the critical angle (in degrees) for the light ray to remain inside the fiber?An engineer is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, she aims a narrow beam of light at a sample of this material, which has a smooth surface. She then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 59.5°. (a)What index of refraction describes the material? n = (b)If some of the incident light (at ?i = 59.5°) enters the material and travels below the surface, what is the angle of refraction (in degrees)?