### Light Refraction and Travel Time in a Water-filled ContainerConsider a cubic container of side \( h \), filled to the rim with water of refractive index \( n_{\text{water}} = 1.33 \). A light ray is incident at the top edge, making an angle \( \theta = 38^\circ \) with the horizontal. In terms of the height, \( h \), and the speed of light in air, \( c \), the time it takes light to go from \( O \) to the bottom of the container is:#### Diagram Explanation:The diagram illustrates the following:- The top left corner of the container is labeled \( O \).- The light ray strikes the water's surface at angle \( \theta \), which is 38 degrees with respect to the horizontal.- The light travels along a path that refracts as it enters the water, continuing to the bottom of the container.- The height \( h \) of the container is shown vertically.- The horizontal travel distance (hypotenuse within the container) is labeled \( d \).#### Time Calculation Options:Given these conditions, the potential time calculations for the light to travel from \( O \) to the bottom of the container are:1. \( t = 1.14h/c \)2. \( t = 1.52h/c \)3. \( t = 1.1h/c \)4. \( t = 1.24h/c \)5. \( t = 1.45h/c \)6. \( t = 1.65h/c \)**Note:** \( c \) represents the speed of light in air.Reflective index \( n \) affects how the light ray bends upon entering the water from air. The calculation of time \( t \) to traverse from point \( O \) to the bottom depends on the refractive properties and the geometric considerations of the path traveled by light within the container.For further details, students are encouraged to delve into Snell's Law for refraction and the principles of light travel in mediums of varying refractive indices.

Concept used: Speed of light decreases in a medium as per the refractive index of the medium.…

Answered: Consider a cubic container of side h,…

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