light ray enters a rectangular block of plastic at an angle of 0₁ = 47.5° and emerges at an angle of 0, = 78.5° as shown in the figure below. n (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, what time interval is required for the light ray to travel through the plastic? ns
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- A light ray propagates in Material 1 with index of refraction n₁ = 1.13, strikes an interface, then passes into Material 2 with index of refraction n₂ = 1.45. The angle of incidence at the interface is 0₁ = 24.3°. Determine the angle of refraction 02. 0₂ = 1 I I Material 1 Material 2A ray of light traveling in air is incident at angle ua on one face of a 90.0° prism made of glass. Part of the light refracts into the prism and strikes the opposite face at point A. If the ray at A is at the critical angle, what is the value of θa?Components of some computers communicate with each other through optical fibers having an index of refraction n = 1.65. What time in nanoseconds is required for a signal to travel 0.17 m through such a fiber? ns
- A light ray enters a rectangular block of plastic at an angle of 0₁ = 44.0° and emerges at an angle of 0₂ = 1 n (a) Determine the index of refraction of the plastic. 80.0° as shown in the figure below. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, what time interval is required for the light ray to travel through the plastic? nsA ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction? Calculate to 1decimal.A light ray in glass arrives at the glass-water interface an angle of 0 = 45° with the normal. The refracted ray in water makes an angle = 75° angle with the normal, as shown in the figure. The index of refraction of water is 1.33. The angle of incidence is now changed to 0 = 25°. What is the new angle of refraction in the water? water glass O O O O O 45.0⁰ 28.5° 35.3° 50.3° 48.1° 81 0
- chapter 25: Problem 9: A beam of light moves through a slab of glass as shown in the figure. The index of refraction of the glass is ng = 1.5. The index of refraction of air is na = 1. The incident angle of the light is θi = 44°. a) If the refraction angle of the light at the upper surface of the slab is θ1, express sinθ1 in terms of θi, na, and ng. b) The incident angle of the light on the lower surface of the slab is θ2. What is the relation between θ1 and θ2? c) The refraction angle of the light on the lower surface of the slab is θf. Express sin(θf) in terms of θ2, na, and ng.An engineer is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, she aims a narrow beam of light at a sample of this material, which has a smooth surface. She then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 59.5°. (a)What index of refraction describes the material? n = (b)If some of the incident light (at ?i = 59.5°) enters the material and travels below the surface, what is the angle of refraction (in degrees)?v