A light ray enters a rectangular block of plastic at an angle 0₁ = 47.2° and emerges at an angle 0₂ = 76.6°, as shown in the figure below. n (a) Determine the index of refraction of the plastic. (b) If the light ray enters the plastic at a point L = 50.0 cm from the bottom edge, how long does it take the light ray to travel through the plastic? ns

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### Educational Content on Refraction

A light ray enters a rectangular block of plastic at an angle \( \theta_1 = 47.2^\circ \) and emerges at an angle \( \theta_2 = 76.6^\circ \), as illustrated in the figure.

#### Diagram Explanation:
- **Figure Description**: The diagram shows a light ray being refracted as it passes through a rectangular block labeled with \( n \), which denotes the index of refraction of the plastic.
- **Angle Indication**: 
  - \( \theta_1 \) represents the angle of incidence as the light ray enters the plastic.
  - \( \theta_2 \) represents the angle of refraction as the light ray exits the plastic.
- **Distance \( L \)**: \( L \) is the vertical distance from the light ray entry point to the bottom edge of the plastic, prescribed as 50.0 cm.

#### Tasks:
(a) **Determine the index of refraction of the plastic**:  
- Use Snell's law, \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \), assuming the light is coming from air where \( n_1 \approx 1 \).

(b) **Calculate the travel time of the light ray through the plastic**:  
- With given \( L = 50.0 \) cm, calculate the time taken for the light to travel using the speed of light in the material, i.e., \( v = \frac{c}{n} \), where \( c \) is the speed of light in vacuum. 

Note: Answer boxes are provided for each part where the calculated values can be entered.
Transcribed Image Text:### Educational Content on Refraction A light ray enters a rectangular block of plastic at an angle \( \theta_1 = 47.2^\circ \) and emerges at an angle \( \theta_2 = 76.6^\circ \), as illustrated in the figure. #### Diagram Explanation: - **Figure Description**: The diagram shows a light ray being refracted as it passes through a rectangular block labeled with \( n \), which denotes the index of refraction of the plastic. - **Angle Indication**: - \( \theta_1 \) represents the angle of incidence as the light ray enters the plastic. - \( \theta_2 \) represents the angle of refraction as the light ray exits the plastic. - **Distance \( L \)**: \( L \) is the vertical distance from the light ray entry point to the bottom edge of the plastic, prescribed as 50.0 cm. #### Tasks: (a) **Determine the index of refraction of the plastic**: - Use Snell's law, \( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) \), assuming the light is coming from air where \( n_1 \approx 1 \). (b) **Calculate the travel time of the light ray through the plastic**: - With given \( L = 50.0 \) cm, calculate the time taken for the light to travel using the speed of light in the material, i.e., \( v = \frac{c}{n} \), where \( c \) is the speed of light in vacuum. Note: Answer boxes are provided for each part where the calculated values can be entered.
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