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The enzyme phospholipase A2 has an optimal pH of 5.5. If a biochemist wants to set up an in vitro assay to screen inhibitors of this enzyme, which buffer system would be BEST?
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- Which of these heterocyclic drugs is likely to be the least soluble in water? Use the Fsp³ parameter to decide. OH Tramadol Chemical Formula: C16H25NO2 YOUR OW Pantoprazole Torasemide Chemical Formula: C16H15F2N3O4S Chemical Formula: C16H20N4O3S Temazepam -OH Chemical Formula: C16H13CIN₂O2 Tioconazole Chemical Formula: C16H13C3N₂OS A. Tramadol B. Pantoprazole C. Torasemide D. Temazepam E. ToconazoleData from enzyme inhibition are used to determine a Kmapp and Vmax PP. Comparison of these values with assays run without inhibitor are used to understand how the inhibition is occurring. This is useful for better understanding the active site as well as the practical aspect of pharmaceutical drugs. Below are idealized Line-Weaver Burke plots of different types of inhibitors. Comnetitive Uncomnetitive Mixed +Inh +Inh 4Inh Anh Inh Anh [S] [S] [S] a. How does the value of Vmax for the enzyme compare to the Vmax PP of the inhibited enzyme for: i. Competitive ii. Uncompetitive iii. Mixed b. How does the value of Km for the enzyme compare to the Km PP of the inhibited enzyme for: i. Competitive ii. Uncompetitive iii. Mixed c. For each situation in Model 1, consider an inhibitor that is better than the one shown on the graph. Answer the following questions for each type of inhibition: i. How would the KmPP change? ii. How would the Vmax PP change?An experiment was carried out to measure the reaction rate of hydrolysis of acetylcholme (substrate) with serum enzymes (Eadie, 1949). In the experiment, two experiments were conducted, namely experiment 1 without using a prostigmine inhibitor and experiment 2 using a prostigmine inhibitor at 1.5 x 10^-7 mol/l. the data obtained are: a. Is prostigmine competitive or noncompetitive inhibitor? b. determine the value of km and rmax for the two experiments, compare
- What would be the best buffering agent to choose if you wanted to buffer an enzyme reaction or tissue culture medium at pH = 7.95? Group of answer choices a. HEPES (4-(2-hydroxyethyl)-1-piperazineethanesulfonic acid); pK = 7.5 b. Histidine; pK1= 1.78; pK2= 5.97; pK3= 8.97 c. Bicarbonate; pK = 6.1 d. Phosphate; pK1 =2.0, pK2 = 6.8; pK3 = 12.5 e. Tris or Tris(hydroxymethyl)aminomethane; pK = 8.07In some organisms, isoleucine can be synthesized in a multi-step procedure (a series of enzymatic reactions), beginning with a molecule of threonine. Keeping that in mind explain the experimental results below. Amount of endproduct Activity of threonine (isoleucine) deaminase None Low Medium High Very high High Moderate Very lowI need hand written solution only
- Mike has determined that enzyme he is attempting to purify has an isoelectric point of 4.5 (pI = 4.5). He has decided to examine anion exchange chromatography as a potential purification step. He tested out using 2 different buffer and linear NaCl gradient on HPLC (like what you did). His results are shown below. Which buffer should Mike uses for his purification (both buffer has pH higher than enzyme’s pI)? Why?A purified protease enzyme from the fungus Aspergillus sp. Is tested in a laboratory. This enzyme was lyophilized as a white powder. When reconstituting with phosphate buffer pH 7.2 the active enzyme is obtained. To check its purity, an electrophoresis is performed where a single band of approximately 70,000 molecular weight is observed. The solution with enzymatic activity was stored at 4ºC for later use. A few days later it was found that the enzymatic activity had been lost and in the electrophoretic analysis, instead of a single band there were three bands of weights 40,000, 20,000 and 10,000. Come up with a reasoned explanation of what might have happened to the enzymeWhat is the minimum inhibitory concentration indicated in the following image?
- Concentrations in biochemical systems are often very dilute. Consequently, scientific notation and logarithms are often used to express concentrations. In scientific notation, numbers are expressed as coefficient x 10" To convert a number to scientific notation, proceed as follows: 1. Move the decimal place so that there is one digit in front of the decimal. 2. Account for the moved decimal in the value of x. If the decimal moved to the right, x is negative; if it moved to the left, x is positive. A logarithm is basically an exponent. Unless otherwise indicated, a logarithm is the a of 10". The numbers after the decimal point are significant; the number before the decimal just identify the location of the decimal point for the number. Notice that it is easy to estimate a logarithm from scientific notation; it's the exponent! Logarithms are commonly used to express the concentration of H. The pH is defined as pH= log (In), where the base number is 2.303. The same general rules as logs…We want to measure the activity of alanine aminotransferase (ALAT) present in a serum. The reaction catalyzed by the enzyme is: Reaction 1: +H3N- glutamate H C CH₂ CH₂ COO -COO + pyruvate CH3 C=0 0.1 M phosphate buffer pH 7.4 : 550 µL 1.2 M alanine : 100 μL CH3 time (min) A340 COO COO™ pyruvate lactate dehydrogenase* (LDH, 300 µg.mL-¹): 50 μL 1.5 mM NADH: 200 μL 0.04 M a-ketoglutarate: 500 μL serum containing ALAT: 600 μL The enzyme reaction is realized in the following conditions: In a 1 cm-cuvette are added: 0 0.915 ALAT NADH + H+ LDH a-cétoglutarate COO * Lactate dehydrogenase (LDH) reduces pyruvate into lactate, with the concomitant oxydation of NADH. This allows to indirectly measure the amount of product formed. Reaction 2: NAD+ 1 0.741 C=O H CH₂ CH₂ COO™ CH3 C-OH COO lactate The reaction is performed at 25 °C and the absorbance at 340 nm is monitored every minute, for 5 min. The absorbance values are given in the table below: Data: alanine ENADH at 340 nm = 6220 M¹.cm1. One…We want to measure the activity of alanine aminotransferase (ALAT) present in a serum. The reaction catalyzed by the enzyme is: Reaction 1: I- *H₂N- glutamate H - C-COO CH₂ CH₂ COO 0.1 M phosphate buffer pH 7.4 : 550 μL 1.2 M alanine: 100 μL CH3 pyruvate CH3 C time (min) A340 CIO O COO The enzyme reaction is alized in the following conditions: In a 1 cm-cuvette are added: COO™ pyruvate lactate dehydrogenase* (LDH, 300 µμg.mL-¹): 50 μL 1.5 mM NADH : 200 μL 0.04 M a-ketoglutarate: 500 µL serum containing ALAT: 600 μµL ALAT NADH + H+ 0 0.915 a-cétoglutarate COO LDH * Lactate dehydrogenase (LDH) reduces pyruvate into lactate, with the concomitant oxydation of NADH. This allows to indirectly measure the amount of product formed. с=0 CH₂ 1 0.741 Reaction 2: NAD+ CH₂ COO™ H-C CH3 OH COO™ lactate alanine H + *H3N-C The reaction is performed at 25 °C and the absorbance at 340 nm is monitored every minute, for 5 min. The absorbance values are given in the table below: Data: ENADH at 340 nm =…