The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.2 cm apart with a 26 kV potential difference between them. The electrons enter through a small hole in the negative plate, accelerate, then exit through a small hole in the positive plate. Assume that the holes are small enough not to affect the electric field or potential. • Part A What is the electric field strength between the plates? Express your answer to two significant figures and include the appropriate units. ? E- Value Units Submit Reauest Answer • Part B With what speed does an electron exit the electron gun if its entry speed is close to zero? Note: The exit speed is so fast that we really need to use the theory of relativity to compute an accurate value. Your answer to part B is in the right range but a little too big. Express your answer to two significant figures and include the appropriate units. Vexit Value Units

The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.2 cm apart with a 26 kV potential difference between them. The electrons enter through a small hole in the negative plate, accelerate, then exit through a small hole in the positive plate. Assume that the holes are small enough not to affect the electric field or potential. • Part A What is the electric field strength between the plates? Express your answer to two significant figures and include the appropriate units. ? E- Value Units Submit Reauest Answer • Part B With what speed does an electron exit the electron gun if its entry speed is close to zero? Note: The exit speed is so fast that we really need to use the theory of relativity to compute an accurate value. Your answer to part B is in the right range but a little too big. Express your answer to two significant figures and include the appropriate units. Vexit Value Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Part B The total electron charge within a radius r equals the integral of p(ri) dV from ri = 0 to ri = r. Set up this integral (but don't solve yet), and use it to write an expression for the total charge (including the proton) within a sphere of radius r. > View Available Hint(s) -2r/a047r? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qencl = 0. %3D Пао3 -2r/a04Tr? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qenel = Qproton - q(r)sphere- The expression for the electron's charge disturbed in the space is -q(r)sphere = ( -2r/ao 47TT? dri, the expression for the total charge is Qencl = Qproton - q(r)phere- e-2r/a04rr? drı, the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo - ( Qenel = Qproton +q(r)sphere- Submit Previous Answers Correct
Part A Two 2.0cm x 2.0cm metal electrodes are spaced 1.4 mm apart and connected by wires to the terminals of a 9.0 V battery. What is the charge on each electrode? Express your answer with the appropriate units. • View Available Hint(s) HÁ Value Units Submit ▼ Part B What is the potential difference between electrodes? Express your answer with the appropriate units. • View Available Hint(s) HÀ AV = Value Units
A uniform electric field exists in the region between two oppositely charged plane parallel plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.80 cm distant from the first, in a time interval of 1.50×108 s For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Accelerating an electron Part A Find the magnitude of this electric field. Express your answer in newtons per coulomb. 1957 ΑΣΦΑ E- Submit Part B Request Answer Find the speed of the electron when it strikes the second plate. Express your answer in meters per second. VE ΑΣΦ| UM ? N/C m/s
II Review | Constants A point charge of -3.00 µC is located in the center of a spherical cavity of radius 6.80 cm inside an insulating spherical charged solid. The charge density in the solid is 7.35 x 10 4 C/m³. Part A Calculate the magnitude of the electric field inside the solid at a distance of 9.30 cm from the center of the cavity. Express your answer with the appropriate units. HA E = Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Find the direction of this electric field. O radially outward O radially inward
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Many chemical reactions release energy. Suppose that at the beginning of a reaction, an electron and proton are separated by 0.125 nm, and their final separation is 0.100 nm. Part A How much electric potential energy was lost in this reaction (in units of eV)? Express your answer using two significant figures. 15] ΑΣΦΑ A PE= Submit Request Answer eV
Part A A typical cell has a membrane potential of -70 mV, meaning that the potential inside the cell is 70 mV less than the potential outside due to a layer of negative charge on the inner surface of the cell wall and a layer of positive charge on the outer surface. This effectively makes the cell wall a charged capacitor. Because a cell's diameter is much larger than the wall thickness, it is reasonable to ignore the curvature of the cell and think of it as a parallel-plate capacitor. How much energy stored in the electric field of a 50-um-diameter cell with a 7.0-nm-thick cell wall whose dielectric constant is 9.0? Express your answer to two significant figures and include the appropriate units. HA ? Uc = Value Units Submit Request Answer < Return to Assignment Provide Feedback
Part N The plates of a parallel-plate capacitor in vacuum are 1.40 mm apart and 2.35 m in area. The charge on the capacitor is 1.15 x 10-C. Calculate the surface charge density on the positive plate Express your answer in coulombs per meter squared. undo redo Tesa keyboard shortcuts Help C/m Submit Requeat Anawer • Part O Calculate the electric field magnitude between the plates. Express your answer with the appropriate units. undo redo fest keyboard shortcuts Help E- Value Units Submit Requent Anawer Part P Find the electric energy density between the plate Express your answer with the appropriate units. Templetes Symbols undo redo feser keyboard shortcuts Help Value Units Submit Request Anewer 11:35 2 A DA/29 25 Cop insert prt ba & 8 5 6 T. Y L J T
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Revie Part A A 1.30 mm-diameter ball bearing has 2.30x109 excess electrons. What is the balIl bearing's potential? Express your answer with the appropriate units. • View Available Hint(s) ol HA AV = Value Units Submit Provide Feedback