Part B The total electron charge within a radius r equals the integral of p(ri) dV from ri = 0 to ri = r. Set up this integral (but don't solve yet), and use it to write an expression for the total charge (including the proton) within a sphere of radius r. > View Available Hint(s) -2r/a047r? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qencl = 0. %3D Пао3 -2r/a04Tr? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qenel = Qproton - q(r)sphere- The expression for the electron's charge disturbed in the space is -q(r)sphere = ( -2r/ao 47TT? dri, the expression for the total charge is Qencl = Qproton - q(r)phere- e-2r/a04rr? drı, the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo - ( Qenel = Qproton +q(r)sphere- Submit Previous Answers Correct Part C Integrate the expression and solve the linear system from previous part to find the total charge Q(r)encl within radius r. Express your answer in terms of the variables Q, r, and ao. • View Available Hint(s) Vα ΑΣφ Q(r)encl = Submit

Part B The total electron charge within a radius r equals the integral of p(ri) dV from ri = 0 to ri = r. Set up this integral (but don't solve yet), and use it to write an expression for the total charge (including the proton) within a sphere of radius r. > View Available Hint(s) -2r/a047r? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qencl = 0. %3D Пао3 -2r/a04Tr? dri. the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo Qenel = Qproton - q(r)sphere- The expression for the electron's charge disturbed in the space is -q(r)sphere = ( -2r/ao 47TT? dri, the expression for the total charge is Qencl = Qproton - q(r)phere- e-2r/a04rr? drı, the expression for the total charge is The expression for the electron's charge disturbed in the space is -q(r)sphere = Jo - ( Qenel = Qproton +q(r)sphere- Submit Previous Answers Correct Part C Integrate the expression and solve the linear system from previous part to find the total charge Q(r)encl within radius r. Express your answer in terms of the variables Q, r, and ao. • View Available Hint(s) Vα ΑΣφ Q(r)encl = Submit

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The diagram below shows a positive point charge placed near a neutral metal cube. The location marked with a × can be ignored. a. Draw the charge distribution within the metal cube and reduce it to an “effective point charge model, as shown in class.b. Is the positive point charge attracted to, repelled by, or unaffected by the metal cube? Please explain using a neat vector diagram to support your arguments.c. In a second identical experiment, the positive point charge +q is replaced by a negative point charge −q. Does a negative point charge interact differently with the metal cube as compared to the positive point charge? Briefly explain your reasoning.
Subject: Ideal Conductors and Capacitors An infinite conducting plane has a hemispherical bump on it with radius R. A point charge Q is located a distance R above the top of the hemisphere, as shown in the figure below. a. Determine the location of the image charges needed to make the electric field perpendicular to the plane and the hemisphere at all points.b. Suppose that the distance A from the given charge Q to the plane is much larger than the radius R of the hemisphere. Show that in this limit, the surface charge density at the top of the hemisphere is 3 times as large as the surface charge density would be on the plane if we simply had a flat plane without the hemispherical bump.
please answer all parts w good explanation
Part 2 after is what is the magnitude of the electric field a distance a from the center of the charged electrostatic conducting cylinder
I need help can you label which one is A,B,C and D
1 and 2
Needs Complete typed solution with 100 % accuracy.
Directions: Assume, unless otherwise specified, that all numbers have at least 3 significant figures. You may work together, but make sure that you are working--not just watching. The magnitude of the force of attraction between the proton and electron in a hydrogen atom is: F = where e is the magnitude of the charge, k is a constant, and r is the radius of the circular orbit. Assume the proton is fixed in place and the electron is in a circular orbit of radius ri. The electron then "jumps" to a new, smaller radius r2. What is the change in the total mechanical energy of the system (in terms ri, r2, e, and k)? Hint: Use dynamics to calculate the kinetic energy for the electron in the initial and final orbits, then calculate the potential energy in both orbits (you will need to develop an expression for the potential energy and remember the force is attractive). Do you know what form the change in mechanical energy takes?
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Please explain the steps/reasoning in your work.
L/2+ L/2 Note: Figure not drawn to scale. 1. A very long, thin, nonconducting cylinder of length L is centered on the y-axis, as shown above. The cylinder has a uniform linear charge density +2.. oint. is located on the y-axis at y = c, where L >> ¢. a) Kecling.c Abh ri gle Circle GEOMETRY AND TRIGONOMETRY i. On the figure shown below, draw an arrow to indicate the direction of the electric field at point F due to the long cylinder. The arrow should start on and point away from the dot. ii. escribe the shape and location of a Gaussian surface that can be used to determine the electric field at point P due to the long cylinder. iii. Use your Gaussian surface to derive an expression for the magnitude of the electric field at point P. E press your answer in terms of 2, c, L, and physical constants, as appropriate. A==bh A = r² C = 277 =r8 Rectangular Solid Vi h Cy.inder Sphere V = r²t Sm V=² S-427² sine Rig Triangle 2+6²=c² cos@= tan= +2 BIL a b C 2x. Q b ADVANCED PLACEMENT PHYSICS C…