An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 23.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 13.5 kV/m (b) Calculate the surface charge density. There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2

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An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 23.0-V potential difference is applied to these plates.
(a) Calculate the electric field between the plates.
13.5
V kV/m
(b) Calculate the surface charge density.
There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2
(c) Calculate the capacitance.
3.95
pF
(d) Calculate the charge on each plate.
90.9
pC
Transcribed Image Text:An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm. A 23.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. 13.5 V kV/m (b) Calculate the surface charge density. There are a number of ways to get to this answer. How do you calculate the electric field due to a uniform surface charge density? nC/m2 (c) Calculate the capacitance. 3.95 pF (d) Calculate the charge on each plate. 90.9 pC
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