A uniform electric field exists in the region between two oppositely charged plane parallel plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.80 cm distant from the first, in a time interval of 1.50×108 s. For related problem-solving tips and strategies, you may want to view a Video Tutor S Solution of Accelerating an electron Part A Find the magnitude of this electric field. Express your answer in newtons per coulomb. Submit Part B ΑΣΦ Request Answer Find the speed of the electron when it strikes the second plate Express your answer in meters per second. ΕΠΑΣΦ ? N/C m/s

A uniform electric field exists in the region between two oppositely charged plane parallel plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.80 cm distant from the first, in a time interval of 1.50×108 s. For related problem-solving tips and strategies, you may want to view a Video Tutor S Solution of Accelerating an electron Part A Find the magnitude of this electric field. Express your answer in newtons per coulomb. Submit Part B ΑΣΦ Request Answer Find the speed of the electron when it strikes the second plate Express your answer in meters per second. ΕΠΑΣΦ ? N/C m/s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Point charge A is on the x-axis at z = -3.00 cm. At x = 1.00 cm on the x-axis its electric field is 2700 N/C. Point charge B is also on the x-axis, at a = 5.00 cm. The absolute magnitude of charge B is twice that of A. Part A Find the magnitude and direction of the total electric field at the origin if both A and B are positive. Express your answer in newtons per coulomb. Enter positive value if the field points in +x-direction and negative value if the field points in -x-direction. Ez = N/C Part B Find the magnitude and direction of the total electric field at the origin if both A and B are negative. Express your answer in newtons per coulomb. Enter positive value if the field points in +x-direction and negative value if the field points in -x-direction. E = N/C
10 nC B. A -5 nC You wish to place a charge at A, which when released will move away from the two charges shown, and then determine the speed of the charge when it gets an infinite distance away from the two charges. The rectangle is 18.4 cm high and 21.9 cm wide. In order for the charge placed at A to move to infinity, you must use an electron a proton When released, approximately which direction will the charge initially accelerate? Image an analog clock face placed at A with 12 o'clock upward. toward ---Select--- v o'clock How fast will the charge be moving when it gets an infinite distance from the two charges? m/s
A proton is placed in a uniform electric field of 2650 N/C. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electron in a uniform field. Part B Calculate the proton's acceleration. Express your answer in meters per second squared. a = 2.5x10¹1 m/s² Submit Correct F a = Part C V = Previous Answers m 4.24×10-16 N 1.67×10-27 kg Calculate the proton's speed after 1.40 us in the field, assuming it starts from rest. Express your answer in meters per second. Π ΑΣΦ 4167.55 105 2.54 × 10¹¹ m/s² ● Submit Previous Answers Request Answer ? m/s
A parallel-plate capacitor is constructed of two horizontal 14.4-cm-diameter circular plates. A 1.9 g plastic bead with a charge of -7.6 nC is suspended between the two plates by the force of the electric field between them. Part A Which plate, the upper or the lower, is positively charged? O Lower. O Upper. O t is impossible to tell. Submit Request Answer Part B What is the charge on the positive plate? Express your answer with the appropriate units. HÀ ? = b Value Units Submit Request Answer
$ = 60° 0 = 30° A proton is projected with initial speed of vo = 500km/s (on the yz-plane) and there is an Uniform Electric Field (blue lines, on the yz-plane) only above the plane which magnitude is 1000N/C. a) Write Electric Field in unit vector notation. b) What is the acceleration and velocity vector for the proton in unit vector notation? c) Find position and velocity vector and their magnitudes at time t = 10ns (Ignore the gravitational force. You can consider the initial point of the proton as origin) (mass of proton = 1.67x10–"kg , charge of proton = 1.60x10–19C , ns = 10-9s)
Two metal spheres, one carrying a 8.0-μCμC charge and the other carrying a -24-μCμC charge, are initially 100 mmmm apart. They are brought in contact with each other and then moved back to their original positions. Part A What is the numerical value of the ratio FEi/FEfFiE/FfE, where FEiFiE is the magnitude of the electric force between the spheres before they are brought in contact and FEfFfE is the magnitude of that force after they are brought together and then moved back to their initial positions?
Two 4.0 kgkg masses are 1.0 mm apart on a frictionless table. Each has 1.0 μCμC of charge. Part A What is the magnitude of the electric force on one of the masses? Part B What is the initial acceleration of each mass if they are released and allowed to move? Express your answer in meters per second squared.
I Review Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in the figure (Figure 1). Part A Find an expression for the electric field E at the center of the semicircle. Hint: A small piece of arc length As spans a small angle A0 = As /R, where R is the radius. Express your answer in terms of the variables Q, L, unit vectors i, j, and appropriate constants. Ην ΑΣφ E = Submit Request Answer Figure < 1 of 1 Part B y Evaluate the field strength if L = cm and Q = 30 nC. Express your answer with the appropriate units. HA ? Center L E = Value Units Submit Previous Answers Request Answer
The nucleus of a 125 Xe atom (an isotope of the element xenon with mass 125 u) is 6.0 fm in diameter. It has 54 protons and charge q = +54e (1 fm = 1 femtometer = 1×10-15m.) Hint: Treat the field of the spherical nucleus as that of a point charge at the center. Part A What is the strength of the electric field 7.0 fm from the surface of the nucleus? Part B What is the direction of the electric field at the point?
In an effort to better understand the behavior of atomic systems, the Danish physicist Niels Bohr (1885-1962) introduced a simple model for the hydrogen atom. In the Bohr model, as it is known today, the electron is imagined to move in a circular orbit about a stationary proton. The force responsible for the electron's circular motion is the electric force of attraction between the electron and the proton. Part A Find the orbital radius for which the kinetic energy of the electron is 2.72 eV. (Note: 1 eV = 1 electron - volt 1.6 × 10-¹⁹ J.) VE ΑΣΦ r = Submit - Request Answer Ć = ? m
A proton enters the uniform electric field produced by the two charged square plates shown below. The plates carry charges +Q and -Q, where the magnitude Q=1 μC. The speed of the proton when it enters the region between the plates is 2 x 107 m/s. 12.0 cm- #3 3 Figure Description Hint a. What is the magnitude of electric field in the region? Assume that the plates are close enough together to be treated as "infinite" planes for electric field between them. N/C. Enter an integer or decimal number [more..] b. What distance d has the proton been deflected downward when it leaves the region between the two plates? Assume that the electrostatic force is the only force on the charge. d= E= Submit Question $ 4 cm. % 5 MacBook Pro <6 A 6 Hey & 7 We 8
A E The picture shows the field lines of a nonuniform electric field and five points A to E in the field. Consider the following statements. Which one is true? This electric field may be due to a negatively charged object located to the left. A positive point charge placed at point C will feel a stronger electric force than at point D. OThe electric field strengths at points B and C are the same because they are on the same field line. OThe electric field strengths at points A and D are both zero because there are no electric field lines on them. A negative point charge placed at point C will feel an electric force pointing to the right.