A uniformly charged thin ring has radius 15.0 cm and total charge 22.5 nC. An electron is placedon the ring's axis a distance 30.0 cm from the center of the ring and is constrained to stay on theaxis of the ring. The electron is then released from rest.For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Aring of charge.Part ADescribe the subsequent motion of the electron.Match the words in the left column to the appropriate blanks in the sentences on the right.is notisrepulsiveattractiveaway fromtowardReset HelpWhen the electron ison either side of thecenter of the ring, thering exerts andirectedforcethecenter of the ring.This force producesoscillatory motion ofthe electron along theaxis of the ring, withamplitude 30.0 cm.The force on theelectronsimple harmonicmotion.of theform F = -kx sothe oscillatory motion

A uniformly charged ring has a radius of r=15.0 cm And total charge Qnet=22.5nC An electron is…

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A uniformly charged thin ring has radius 13.0 cm and total charge 23.0 nC. An electron is placed on the ring's axis a distance 26.0 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A ring of charge. Find the speed of the electron when it reaches the center of the ring. Express your answer in meters per second. ΑΣΦ V = m/s
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Two identical balls of 29.5 g are suspended from threads of length 1.1 m and carry equal charges as shown in the figure. Each ball is 1.5 cm from the centerline.a) Assume that the angle Θ is so small that its tangent can be replaced by its sine. This is called the small angle approximation and means that for small angles sin(Θ)=tan(Θ). Find the magnitude of charge on one of the balls. b) Now, assume the two balls are losing charge to the air very slowly. That means they'll be slowly approaching each other. If a ball is moving at an instantaneous speed of 2.50E−05 m/s, at what rate is the ball losing charge? Start by writing the speed of the ball and the rate of change of the charge as symbolic derivatives, and then relate those derivatives. Give your answer in Coulombs per second (C/s). Note that because the balls are losing charge so slowly, we can still use our results from the previous part, as the system is almost in equilibrium. Give your answer as a magnitude.
Problem * : Two dipoles are placed on the corners of a rectangle with dimensions L=3.4 cm and W=0.1 cm as shown in the figure. Dipole 1 has charge adipole 1-1. 1 nC with charge separation S₁ =0.9 mm while dipole 2 has charge adipole 2-0.5 nC with charge separation S₂ = 2.4 mm, respectively. Another two positive point charges Q₁ =27 nC and Q2-1 nC were placed on the other corners of the same rectangle as shown. E Dipole 1 Y S₁ Q₂ ->Find the net force on Q₁. 2. ( FQ1 = N ‒‒‒‒‒‒ W > Find the electric field vector due to the two dipoles at the location of Q₁. ----- Q₁ Dipole 2
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A uniformly charged thin ring has radius 15.0 cm and total charge 20.0 nC. An electron is placed on the ring's axis a distance 30.0 cm from the center of the ring and is constrained to stay on the axis of the ring. The electron is then released from rest. For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of A ring of charge. ▶ Part A Part B Find the speed of the electron when it reaches the center of the ring. Express your answer in meters per second. VE ΑΣΦ V= Submit Provide Feedback Request Answer Constants ? m/s Next >
Two point charges are located at the positive x-axis of a coordinate system. Charge L = -8µC is located 3 cm away from the origin while charge M = 3 nC is 2 cm away from the origin. Find the following: a. FL on M b. FM on L
Consider the following. B 0.500 mm 60.0° (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 1.80 pC, B = 6.60 pC, and C = -4.40 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? magnitude N/C direction ° counterclockwise from the +x axis (b) If the charge of cell A were doubled, how would the electric field at cell A change? O The magnitude of the field would be doubled. O The field would be unchanged. O The magnitude of the field would be halved. O The magnitude of the field would be quadrupled.
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In the figure, two identical spheres of radius R are set up a distance d away from each other (d is the distance from the center of one to the center of the other). One sphere has charge +Q and is centered at x = 0. The other sphere has a charge -Q and is centered at x = d. You are using this set-up to accelerate a small particle with charge q and mass m. The particle starts at a position x, and ends up at a position xy-d-x. (The distance from the positive sphere to x, is equal to the distance from x, to the negative sphere.) The values in this problem are: d-4.70 m, R = 0.16 m, Q-8.65x10 C, q-6.37x10 C m-1.87x105 kg. x = 0.78 m If the small charge starts at rest, what is the final speed of the charge when it reaches x? Give your answer in m/s to at least three digits, to avoid being counted incorrect due to rounding. Note: You can assume that the spheres are far enough apart that the charge on the sphere is uniformly distributed on their surfaces. R,+Q R₁-Q
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