The differential form of the Helmholtz free energy–for a closed, one-component system-is given below. dA = –P dV – SdT a) Starting from A U – TS, derive the above expression. b) Show that AA = AU – TAS. Be sure to clearly state any assumptions or conditions. c) The Helmholtz energy can be used to determine the spontaneity of a process in the same way as the Gibbs energy: at equilibrium, dA = -PdV – SdT +2 Hi dNi, dA = 0 Under what conditions and/or for what types of systems would it be easier to use the Helmholtz free energy, as opposed to the Gibbs free energy? Briefly explain. Hint: Another way to think of this question is, “Why do chemists and biochemists
The differential form of the Helmholtz free energy–for a closed, one-component system-is given below. dA = –P dV – SdT a) Starting from A U – TS, derive the above expression. b) Show that AA = AU – TAS. Be sure to clearly state any assumptions or conditions. c) The Helmholtz energy can be used to determine the spontaneity of a process in the same way as the Gibbs energy: at equilibrium, dA = -PdV – SdT +2 Hi dNi, dA = 0 Under what conditions and/or for what types of systems would it be easier to use the Helmholtz free energy, as opposed to the Gibbs free energy? Briefly explain. Hint: Another way to think of this question is, “Why do chemists and biochemists
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**The Differential Form of Helmholtz Free Energy**
For a closed, one-component system, the differential form of the Helmholtz free energy is given by:
\[ dA = -PdV - SdT \]
Tasks:
a) **Starting from \( A \equiv U - TS \), derive the above expression.**
b) **Show that \( \Delta A = \Delta U - T \Delta S \).** Be sure to clearly state any assumptions or conditions.
c) **The Helmholtz energy can be used to determine the spontaneity of a process in the same way as the Gibbs energy:**
\[ dA = -PdV - SdT + \sum_{i} \mu_i dN_i, \]
At equilibrium, \( dA = 0 \).
**Question:**
Under what conditions and/or for what types of systems would it be easier to use the Helmholtz free energy, as opposed to the Gibbs free energy? Briefly explain.
*Hint: Another way to think of this question is, "Why do chemists and biochemists generally use \( \Delta G \) and not \( \Delta A \)?"*](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70b600a9-4fe2-43b6-bf71-9653b547ae78%2F1da99f8a-d002-488e-a4a2-82f5d768dbcb%2Ffphnq3_processed.png&w=3840&q=75)
Transcribed Image Text:**The Differential Form of Helmholtz Free Energy**
For a closed, one-component system, the differential form of the Helmholtz free energy is given by:
\[ dA = -PdV - SdT \]
Tasks:
a) **Starting from \( A \equiv U - TS \), derive the above expression.**
b) **Show that \( \Delta A = \Delta U - T \Delta S \).** Be sure to clearly state any assumptions or conditions.
c) **The Helmholtz energy can be used to determine the spontaneity of a process in the same way as the Gibbs energy:**
\[ dA = -PdV - SdT + \sum_{i} \mu_i dN_i, \]
At equilibrium, \( dA = 0 \).
**Question:**
Under what conditions and/or for what types of systems would it be easier to use the Helmholtz free energy, as opposed to the Gibbs free energy? Briefly explain.
*Hint: Another way to think of this question is, "Why do chemists and biochemists generally use \( \Delta G \) and not \( \Delta A \)?"*
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