Taking into account that dG = Vdp –SdTA) write the Maxwell relation between changes in volume and entropyWhat is true about temperature? A) V = (ôp/ôS)T B) V = (ôG/ôp)v C) V = (ôG/ôT), D) V = (ôS/ôT),

The four maxwell equations are as shown below. Hence the maxwell relation between changes in volume…

Answered: Taking into account that dG = Vdp –SdT…

Chemistry

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ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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P3B.4 The molar heat capacity of N,(g) in the range 200 K to 400 K is given by Cm/(JK mol) = 28.58 + 3.77 x 10°(T/K). Given that the standard molar entropy of N,(g) at 298 K is 191.6 J Kmol, calculate the value at 373 K. Repeat the calculation but this time assuming that C, is independent of %3D D.m temperature and takes the value 29.13 J K mol. Comment on the difference between the results of the two calculations.
Part B Based on the value of A,U = -1370 kJ mol-1,determine the value of A,H for the combustion of ethanol at 298 K. C2H5OH(I) + 3 O2(g) →2 CO2(g) + 3 H,0() Enter your answer using four significant figures. Πνα ΑΣφ ? A,H = kJ mol 1
1. (a) In reaching equilibrium, how much heat transfer occurs from 1.2 kg of water at 40°C when it is placed in contact with 1.2 kg of 20°C water? Specific heat of water c=4186 J/(kg°C) Hint: If the masses of water are equal, what is the equilirium temperature of the water mixture? Q= ✓ J (b) What is the change in entropy due to this heat transfer? AS total ✔J/K (c) How much work is made unavailable, taking the lowest temperature to be 20°C? = W unavailable ✓ J
Calculate the change in entropy that occurs in the system when 1.61 mol of diethyl ether (C4H10O) condenses from a gas to a liquid at its normal boiling point (34.6 °C). The heat of vaporization is 26.5 kJ/mol. Express your answer with the appropriate units. AS = μÅ Value Units ?
(a) Suppose that attractions are the dominant interaction between gas molecules, and the equation of state is p = nRT/V – n2a/V2. Determine the work (W(non-ideal gas)) of reversible, isothermal expansion of such a gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol, T = 300 K, and a = 3.621 atm-L2/mol2. Watch your units. (b)Determine the work (W(ideal gas) of reversible, isothermal expansion of an ideal gas from initial volume V (initial) = 20.0 L to final volume V(final) = 40.0 L if n = 2.00 mol and T = 300 K. (c) Show the difference W(non-ideal) – W(ideal). If all your calculations are done correctly, this result shows you the effect of attractive interaction between gas particles on the work done by the system.
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This question has multiple parts. Work all the parts to get the most points. The Gibbs Free Energy equation is given by the equation: AG = AH - TAS Where: AG = Gibbs Free Energy change AH = Enthalpy change T = temperature AS = Entropy change In order to solve for the temperature, T, in two steps you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-hand side of the expression: (Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.) +AG = +AH - TAS Drag and drop your selection from the following list to complete the answer: 1 1 -ΔΗ ΔΗ AH AH

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Taking into account that dG = Vdp –SdT A) write the Maxwell relation between changes in volume and entropy What is true about temperature? A) V = (ôp/ôS)T B) V = (ôG/ôp)v C) V = (ôG/ôT), D) V = (ôS/ôT),