C. Consider a chemical reaction. At a temperature T, = 300. K and an external pressure P, the enthalpy of reaction is A, H (T,, P) = 400.J and the Gibbs potential of reaction is A, G(T,,P) = 100. J. %3D We will prove later that Gibbs-Helmholtz relation can also extended to describe chemical reactions ((), ArH Assuming this relation to hold true, consider the following: ƏT T2
C. Consider a chemical reaction. At a temperature T, = 300. K and an external pressure P, the enthalpy of reaction is A, H (T,, P) = 400.J and the Gibbs potential of reaction is A, G(T,,P) = 100. J. %3D We will prove later that Gibbs-Helmholtz relation can also extended to describe chemical reactions ((), ArH Assuming this relation to hold true, consider the following: ƏT T2
Chemistry
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Chapter1: Chemical Foundations
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Assuming that deltarH s independent of temperature, determine deltarG(T2,P) for T2= 400K
![C. Consider a chemical reaction. At a temperature \( T_1 = 300. \, \text{K} \) and an external pressure \( P \), the enthalpy of reaction is \( \Delta_r H(T_1, P) = 400. \, \text{J} \) and the Gibbs potential of reaction is \( \Delta_r G(T_1, P) = 100. \, \text{J} \).
We will prove later that Gibbs-Helmholtz relation can also be extended to describe chemical reactions
\[
\left( \frac{\partial}{\partial T} \left( \frac{\Delta_r G}{T} \right) \right)_P = -\frac{\Delta_r H}{T^2}.
\]
Assuming this relation to hold true, consider the following:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F37df213a-2c14-4822-a979-37f159717cfc%2F3912f9d4-75fa-41d3-b738-f028f0b065ad%2Fg1fo2a9_processed.png&w=3840&q=75)
Transcribed Image Text:C. Consider a chemical reaction. At a temperature \( T_1 = 300. \, \text{K} \) and an external pressure \( P \), the enthalpy of reaction is \( \Delta_r H(T_1, P) = 400. \, \text{J} \) and the Gibbs potential of reaction is \( \Delta_r G(T_1, P) = 100. \, \text{J} \).
We will prove later that Gibbs-Helmholtz relation can also be extended to describe chemical reactions
\[
\left( \frac{\partial}{\partial T} \left( \frac{\Delta_r G}{T} \right) \right)_P = -\frac{\Delta_r H}{T^2}.
\]
Assuming this relation to hold true, consider the following:
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