The data in the table below were obtained for the reaction: 2A+ 2B → 3C Experiment Number [A] (M) [В] (M) Initial Rate (M/s) 1 0.186 0.451 2.26 0.930 0.451 11.3 0.186 1.35 20.34 The rate law for this reaction is rate = O A. k[A]2 O B. k[A]²[B]2 O. k[A][B] O D. K[A][B]? O E. k[A]²[B]
The data in the table below were obtained for the reaction: 2A+ 2B → 3C Experiment Number [A] (M) [В] (M) Initial Rate (M/s) 1 0.186 0.451 2.26 0.930 0.451 11.3 0.186 1.35 20.34 The rate law for this reaction is rate = O A. k[A]2 O B. k[A]²[B]2 O. k[A][B] O D. K[A][B]? O E. k[A]²[B]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![The data in the table below were obtained for the reaction:
2A+ 2B → 3C
Experiment Number
[A] (M)
[В] (M)
Initial Rate (M/s)
1
0.186
0.451
2.26
0.930
0.451
11.3
0.186
1.35
20.34
The rate law for this reaction is rate =
O A. k[A]2
O B. k[A]²[B]2
O. k[A][B]
O D. K[A][B]?
O E. k[A]²[B]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F496399c4-f224-4c2a-bcf9-0f786d8cece3%2Fcea4f7ed-adbc-4ce1-bdd1-304d25b36d6c%2F3ybtkqb_processed.png&w=3840&q=75)
Transcribed Image Text:The data in the table below were obtained for the reaction:
2A+ 2B → 3C
Experiment Number
[A] (M)
[В] (M)
Initial Rate (M/s)
1
0.186
0.451
2.26
0.930
0.451
11.3
0.186
1.35
20.34
The rate law for this reaction is rate =
O A. k[A]2
O B. k[A]²[B]2
O. k[A][B]
O D. K[A][B]?
O E. k[A]²[B]
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