Note: The reaction below is first order with respect to NO and second order with respe Cl, Determine the value of the rate constant and write the rate law. 2 NO (3) + Cl2 (e) → 2 NOCI (2) Experiment Initial [NO] Initial [Cl2] Initial Rate (M/s) 2.27 x 10-5 9.08 x 10-5 4.55 x 10-5 1 0.0125 M 0.0255 0.0125 M 0.0510 3. 0.0250 M 0.0255 Rate = 0.00370 M2s [NO2e [Cl@l' O Rate = 2.79 M2s [NOe [Cle]! O Rate = 0.0712 M's NO2e)] [Cl] O Rate = 5.70 M-25 [NOl' [Cle)l Rate = 5.70 M2s" [NO2 [Clel Rate = 2.79 M2s [NO2)l [Cl@l* Rate = 0.00370 Ms [NOel' [Cl@]* Rate = 0.0712 M's INO2] [Cl(g)]

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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The reaction below is first order with respect to NO and second order with respect
Cl, Determine the value of the rate constant and write the rate law.
2 NO (2) + Cl2 (g)
2 NOC1
(g)
Initial [Cl2]
Initial Rate (M/s)
Experiment
Initial [NO]
0.0125 M-
0.0255
2.27 x 10-
1
0.0125 M
0.0510
9.08 x 10-5
3.
0.0250 M
0.0255
4.55 x 10-5
Rate = 0.00370 M-2s [NO2el [Cl@]
Rate = 2.79 M2s [NO2 [Cl(g)]
ORate= 0.0712 M-'s [NO] [Clgl*
Rate = 5.70 Ms [NOl' [Clze1
Rate = 5.70 M2s [NOl [Cl@l'
2,41
[Cl(e)
Rate = 2.79 Ms" [NOe)l' [Cle
भजको को तो
Rate = 0.00370 M²s [NO2l [Cl2el
Rate = 0.0712 M's [NO2] [Cl]
Transcribed Image Text:Note: This is a The reaction below is first order with respect to NO and second order with respect Cl, Determine the value of the rate constant and write the rate law. 2 NO (2) + Cl2 (g) 2 NOC1 (g) Initial [Cl2] Initial Rate (M/s) Experiment Initial [NO] 0.0125 M- 0.0255 2.27 x 10- 1 0.0125 M 0.0510 9.08 x 10-5 3. 0.0250 M 0.0255 4.55 x 10-5 Rate = 0.00370 M-2s [NO2el [Cl@] Rate = 2.79 M2s [NO2 [Cl(g)] ORate= 0.0712 M-'s [NO] [Clgl* Rate = 5.70 Ms [NOl' [Clze1 Rate = 5.70 M2s [NOl [Cl@l' 2,41 [Cl(e) Rate = 2.79 Ms" [NOe)l' [Cle भजको को तो Rate = 0.00370 M²s [NO2l [Cl2el Rate = 0.0712 M's [NO2] [Cl]
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