The following initial rate data are for the reaction of ICl with hydrogen:\[ 2 \text{ICl} + \text{H}_2 \rightarrow \text{I}_2 + 2 \text{HCl} \]| Experiment | \([\text{ICl}]_0, \text{ M}\) | \([\text{H}_2]_0, \text{ M}\) | Initial Rate, \(\text{M} \cdot \text{s}^{-1}\) ||------------|------------------|----------------|----------------------------|| 1 | 0.116 | 0.171 | 0.00621 || 2 | 0.232 | 0.171 | 0.0124 || 3 | 0.116 | 0.342 | 0.0248 || 4 | 0.232 | 0.342 | 0.0497 |Complete the rate law for this reaction in the box below.Use the form \(k[\text{A}]^m[\text{B}]^n\), where '1' is understood for \(m\) or \(n\) and concentrations taken to the zero power do not appear. Don't enter 1 for \(m\) or \(n\).Rate = \(\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\)\[ k = \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \text{M}^{-2} \cdot \text{s}^{-1} \]

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following initial rate data are for the reaction of IC1 with hydrogen: 2IC1 + H₂ → I₂ + 2HCl eriment [IC], M [H₂0, M 0.116 0.171 0.232 0.171 0.116 0.342 0.232 0.342 plete the rate law for this reaction in the box below. the form k[A] [B]", where '1' is understood for m or n and concentrations taken to the zero power do not appear. t enter 1 for m or n. = Initial Rate, M. s-¹ 0.00621 0.0124 0.0248 0.0497 M-2.s ¹ -1

following initial rate data are for the reaction of IC1 with hydrogen: 2IC1 + H₂ → I₂ + 2HCl eriment [IC], M [H₂0, M 0.116 0.171 0.232 0.171 0.116 0.342 0.232 0.342 plete the rate law for this reaction in the box below. the form k[A] [B]", where '1' is understood for m or n and concentrations taken to the zero power do not appear. t enter 1 for m or n. = Initial Rate, M. s-¹ 0.00621 0.0124 0.0248 0.0497 M-2.s ¹ -1

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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