141 For the reactionExperiment1232C+2D, the following data were obtained.[B] (mol L-1)Rate (mol L-1 s-1)0.2000.0003600.0007200.000720(A) (mol L-1)0.1000.2000.1000.2000.400A) the rate law is therefore: rate= K[A]B) the rate law is therefore: rate= K[A]²[B][B]C) the rate law is therefore: rateD) the rate law is therefore: rate[A][B]²E) the rate law is therefore: rate= K[A][B]

Answered: Image /qna-images/answer/76476a46-0561-42fd-b11f-4a15b6729e9e.jpg

14) For the reaction Experiment 2 3 2C+2D, the following data were obtained. (A] (mol L-1) [B] (mol L-1) Rate (mol L-1 s-1) 0.100 0.200 0.000360 0.200 0.000720 0.400 0.000720 0.200 0.100 A) the rate law is therefore; rate= K[A] B) the rate law is therefore: rate= K[A]²[B] C) the rate law is therefore: rate [B] D) the rate law is therefore: rate=A[A][B]² E) the rate law is therefore: rate= A[A][B]

14) For the reaction Experiment 2 3 2C+2D, the following data were obtained. (A] (mol L-1) [B] (mol L-1) Rate (mol L-1 s-1) 0.100 0.200 0.000360 0.200 0.000720 0.400 0.000720 0.200 0.100 A) the rate law is therefore; rate= K[A] B) the rate law is therefore: rate= K[A]²[B] C) the rate law is therefore: rate [B] D) the rate law is therefore: rate=A[A][B]² E) the rate law is therefore: rate= A[A][B]

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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