Given the following experimental data and rate law: Trial [A] [B] Rate Number (mol/L) (mol/L) (mol/L-min) Trial 1 0.30 0.40 0.56 Trial 2 0.90 0.40 1:68 Trial 3 0.30 0.80. 1.12 rate = k [A]m[B]" %3D Which two trials would need to be compared to find the order n? O 3÷1 O 2÷1 O 2÷3

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Given the following experimental data and rate law:

| Trial Number | [A] (mol/L) | [B] (mol/L) | Rate (mol/L·min) |
|--------------|-------------|-------------|------------------|
| Trial 1      | 0.30        | 0.40        | 0.56             |
| Trial 2      | 0.90        | 0.40        | 1.68             |
| Trial 3      | 0.30        | 0.80        | 1.12             |

Rate law equation:  
\[ \text{rate} = k [A]^m[B]^n \]

Question:  
Which two trials would need to be compared to find the order \( n \)?

Options:
- ○ 3÷1
- ○ 2÷1
- ○ 2÷3
Transcribed Image Text:Given the following experimental data and rate law: | Trial Number | [A] (mol/L) | [B] (mol/L) | Rate (mol/L·min) | |--------------|-------------|-------------|------------------| | Trial 1 | 0.30 | 0.40 | 0.56 | | Trial 2 | 0.90 | 0.40 | 1.68 | | Trial 3 | 0.30 | 0.80 | 1.12 | Rate law equation: \[ \text{rate} = k [A]^m[B]^n \] Question: Which two trials would need to be compared to find the order \( n \)? Options: - ○ 3÷1 - ○ 2÷1 - ○ 2÷3
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