For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. if the rate doubles, then the order for A is 1. • if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: order rate₁ rate2 What is the reaction order with respect to A? [reactant]₁ [reactant]2 Rate = K[A]orderA[B]orderB (- -) [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.379 0.401 0.156 Trial 2 0.758 0.401 0.312 Trial 3 0.379 0.802 0.156 Trial 4 0.673 0.648 0.277
For cases where [A] exactly doubles: • if the rate does not change, the order for A is 0. if the rate doubles, then the order for A is 1. • if the rate quadruples, the order for A is 2. For more complex cases, use the general equation: order rate₁ rate2 What is the reaction order with respect to A? [reactant]₁ [reactant]2 Rate = K[A]orderA[B]orderB (- -) [A], mol/L [B], mol/L rate, mol/(L-min) Trial 1 0.379 0.401 0.156 Trial 2 0.758 0.401 0.312 Trial 3 0.379 0.802 0.156 Trial 4 0.673 0.648 0.277
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![For cases where [A] exactly doubles:
• if the rate does not change, the order for A is 0.
• if the rate doubles, then the order for A is 1.
• if the rate quadruples, the order for A is 2.
For more complex cases, use the general equation:
order
rate₁
rate2
= (
[reactant],
[reactant]₂
What is the reaction order with respect to A?
Rate = K[A]orderA[B]orderB
[A], mol/L [B], mol/L rate, mol/(L-min)
Trial 1
0.379
0.401
0.156
Trial 2
0.758
0.401
0.312
Trial 3
0.379
0.802
0.156
Trial 4 0.673
0.648
0.277](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F410de4e1-4314-42c8-8492-083aa9a0c480%2F78d7564b-c755-4fa3-9460-59da9a2225fc%2Fjk7l6vr_processed.png&w=3840&q=75)
Transcribed Image Text:For cases where [A] exactly doubles:
• if the rate does not change, the order for A is 0.
• if the rate doubles, then the order for A is 1.
• if the rate quadruples, the order for A is 2.
For more complex cases, use the general equation:
order
rate₁
rate2
= (
[reactant],
[reactant]₂
What is the reaction order with respect to A?
Rate = K[A]orderA[B]orderB
[A], mol/L [B], mol/L rate, mol/(L-min)
Trial 1
0.379
0.401
0.156
Trial 2
0.758
0.401
0.312
Trial 3
0.379
0.802
0.156
Trial 4 0.673
0.648
0.277
Expert Solution
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Step 1
The relation between the concentration of the reactants and the rate of reaction is expressed by the rate law. The rate law of a reaction is determined experimentally. The sum of the exponent term in the rate law for a chemical reaction is known as the order of the reaction.
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