Consider this reaction: CICH₂CH₂C1 (g) → CH₂CHC1 (g) + HC1 (g) At a certain temperature it obeys this rate law. rate = = (0.00818 M S ¹) [CICH₂CH₂CI]² Suppose a vessel contains CICH₂CH₂Cl at a concentration of 1.16 M. Calculate how long it takes for the concentration of CICH₂CH₂Cl to decrease to 11.0% of its initial value. You may assume no other reaction is important. Round your answer to 2 significant digits. s □

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### Chemical Reaction and Rate Law

**Consider the following reaction:**

\[ \text{CICH}_2\text{CH}_2\text{Cl} \, (g) \rightarrow \text{CH}_2\text{CCl} \, (g) + \text{HCl} \, (g) \]

**At a given temperature, the reaction obeys the following rate law:**

\[ \text{rate} = (0.00818 \, \text{M}^{-1} \text{s}^{-1}) [\text{CICH}_2\text{CH}_2\text{Cl}]^2 \]

**Problem Statement:**

Suppose a vessel contains CICH₂CH₂Cl at a concentration of 1.16 M. Calculate how long it takes for the concentration of CICH₂CH₂Cl to decrease to 11.0% of its initial value. Assume that no other reaction is significant.

**Instructions:**
- Round your answer to 2 significant digits.

**Calculation:**

The detailed steps to solve this calculation will include:
1. Determining the final concentration of CICH₂CH₂Cl, which is 11.0% of 1.16 M.
2. Using the integrated rate law for a second-order reaction to find the time required for the concentration to decrease to this value.

**Final Answer Box:**
\[ \boxed{\phantom{0}} \, \text{s} \]

**Interactive Options:**
- There are interactive controls below the calculation box allowing users to input their answers, clear ("\[\mathsf { \times }\]") their work, and find help or hints ("?").
Transcribed Image Text:### Chemical Reaction and Rate Law **Consider the following reaction:** \[ \text{CICH}_2\text{CH}_2\text{Cl} \, (g) \rightarrow \text{CH}_2\text{CCl} \, (g) + \text{HCl} \, (g) \] **At a given temperature, the reaction obeys the following rate law:** \[ \text{rate} = (0.00818 \, \text{M}^{-1} \text{s}^{-1}) [\text{CICH}_2\text{CH}_2\text{Cl}]^2 \] **Problem Statement:** Suppose a vessel contains CICH₂CH₂Cl at a concentration of 1.16 M. Calculate how long it takes for the concentration of CICH₂CH₂Cl to decrease to 11.0% of its initial value. Assume that no other reaction is significant. **Instructions:** - Round your answer to 2 significant digits. **Calculation:** The detailed steps to solve this calculation will include: 1. Determining the final concentration of CICH₂CH₂Cl, which is 11.0% of 1.16 M. 2. Using the integrated rate law for a second-order reaction to find the time required for the concentration to decrease to this value. **Final Answer Box:** \[ \boxed{\phantom{0}} \, \text{s} \] **Interactive Options:** - There are interactive controls below the calculation box allowing users to input their answers, clear ("\[\mathsf { \times }\]") their work, and find help or hints ("?").
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