The d = 13-mm-diameter solid rod passes through a D = 20-mm-diameter hole in the support plate. When a load Pis applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 15 mm. The rod head has a diameter of a = 31 mm, and the head has a thickness of t= 10 mm. If the normal stress produced in the rod by load Pis 150 MPa, determine (a) the bearing stress acting between the support plate and the rod head. (b) the average shear stress produced in the rod head. (c) the punching shear stress produced in the support plate by the rod head.
The d = 13-mm-diameter solid rod passes through a D = 20-mm-diameter hole in the support plate. When a load Pis applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 15 mm. The rod head has a diameter of a = 31 mm, and the head has a thickness of t= 10 mm. If the normal stress produced in the rod by load Pis 150 MPa, determine (a) the bearing stress acting between the support plate and the rod head. (b) the average shear stress produced in the rod head. (c) the punching shear stress produced in the support plate by the rod head.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:The d = 13-mm-diameter solid rod passes through a D = 20-mm-diameter hole in the support plate. When a load Pis applied to the
rod, the rod head rests on the support plate. The support plate has a thickness of b = 15 mm. The rod head has a diameter of a = 31
mm, and the head has a thickness of t= 10 mm. If the normal stress produced in the rod by load Pis 150 MPa, determine
(a) the bearing stress acting between the support plate and the rod head.
(b) the average shear stress produced in the rod head.
(c) the punching shear stress produced in the support plate by the rod head.
Support
Plate
- Hole diameter D
P
Rod
Нead
a
Calculate the cross-sectional area of the rod.
Answer: Arod = i
mm2
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