The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size isn=761 and the test statistic is t=55.668. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.10.State the null and alternative hypotheses.H₁>2.842.84(Type integers or decimals. Do not round.)The test statistic is(Round to two decimal places as needed.)

Step 1:Given data : Sample size n=761degrees of freedom df=n−1=761−1=760Significance level α=0.10…

Answered: The claim is that smokers have a mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In the population of senior students at Shermer High School, the proportion who plan to attend college is 0.64. In a random sample of 100 students from this population, the proportion who plan to attend college is 0.75. We would call the value 0.64 a P-value. z-score. parameter statistic significance level.
Q: Using the data (provided below this question) test the hypotheses that the mean difference in writing and reading scores is zero and that the mean difference in math and science scores is zero. Use the paired-sample procedure. Use a 5% significance level if the problem doesn’t give an alpha. Note: Please only provide the t stat, p(T<=t) value and critical value. No need to explain the steps. School District Writing Reading Math Citizenship Science All Indian Hill 95 98 89 95 91 83 Wyoming 98 96 86 93 87 81 Mason City 96 92 85 94 86 72 Madiera 94 95 88 82 88 69 Mariemont 99 92 74 89 88 68 Sycamore 85 88 80 87 84 68 Forest Hills 93 91 73 85 88 67 Kings Local 92 86 78 82 78 64 Lakota 90 88 73 85 81 64 Loveland 85 93 72 86 86 61 Southwest 92 82 73 78 73 58 Fairf ield 90 86 71 83 77 57 Oak Hills 88 86 75 77 79 57 Three Rivers 87 85 66 84 77 56 Milford 82 86 72 82 76 53 Ross 84 85 66 75 78 52 West Clermont 88 83 63 73 70 48 Reading 88 80 58 76 75…
Suppose a statistician named Big Daddy thinks that the average monthly electric bill for Houston in August is more than $150. Using sample data from a normal population, Big Daddy obtains a test statistic of z = 1.06. Determine the P-value and state the conclusion at the 5% level of significance.
Please let me know the answer
The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n 810 and the test statistic is t=55.337. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. State the null and alternative hypotheses. Ho H H₁H (Type integers or decimals. Do not round.)
If applicable, use the appropriate test to determine the average nicotine content which differs. In responding, construct and test any appropriate hypothesis.
Road Transport Department claims that the mean speed of cars on a highway is 114 km/h. An insurance company took a random sample of 21 cars driven on a highway and found that the test statistic is -2.2913. Can we accept the Road Transport Department's claim at 5% level of significance? (Hint: o unknown)
With 0.05 significance level, H1: p > 0.5, and the value of test statistics is z = 1.25. Then the P-value is equal to 0.8944 -0.1056 0.1056 None
Assume that a simple random sample has been selected from a normally distributed population. State the final conclusion.Test the claim that the mean lifetime of car engines of a particular type is greater than 220,000 miles. Sample data are summarized as n = 23, and s = 11,500 miles. Use a significance level of α = 0.01.H0: μ = 220,000 HA: μ > 220,000State your conclusion about H0. Choose the best answer below: A. Reject HA B. Do not reject H0 C. Do not reject HA D. Reject H0 E. Cannot draw a conclusion for information given
Please please answer that
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
The p-value for a t-statistic was .008. What is the best way to report the level of significance? p<.008 p<.05 p<.01 p<.001

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