If the test requires that the results be statistically significant at a level of α = 0.05, fill in the blanks and complete the sentencesthat explain the test decision and conclusion.The decision is torejectthe null hypothesis. Thereisenough evidence at a significance level ofa = 0.05 that the mean weight for U.S. women of age 40-49 who smoke daily is less than 169.976 pounds.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Women athletes at UČLA have a long-term graduation rate of 96%. Over the past several years, a random sample of 40 women athletes at UCLA showed that 37 eventually graduated. Do the data indicate that the population proportion of women athletes who graduate from UCLA is now less than 96%? Use a 5% significance level. You must identify the following in your answer in order to receive credit. Upload your response 1. State Ho and H1 2. Find the test statistic z (Round to two decimal places) 3. Find the p-value (Round to four decimal places) 4. Indicate the calculator key you used. 5. Do you reject Ho or fail to reject Ho? 6. State your conclusion: Upload Choose a File « Previous Next
Use the table to answer the questions. Compute the prevalence of true diabetes in this population. Compute the sensitivity of the test. Explain in words what your sensitivity answer means. (Do not just write the definition; include your result!) Compute the specificity of the test. Explain in words what your specificity answer means. (Do not just write the definition; include your result!) Compute the positive predictive value of the test. Explain in words what your positive predictive value answer means. (Do not just write the definition; include your result!)
During the 1990s, the fatality rate for lung cancer was 80 per 100,000 people. After the turn of the century and the establishment of newer treatments and adjustment in public health advertising, a random sample of 10,000 people exhibits only six deaths due to lung cancer. Test at the 0.05 significance level whether that data are proof of a reduced fatality rate for lung cancer. b. Make the decision rule. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.) c. Evaluate the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.56 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is greater than the governments' safety limit. The null and alternative hypotheses are H0: μ=0.56 ppm, Ha: μ>0.56 ppm. Complete parts (a) through (e) below. d. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms equals the safety limit of 0.56 ppm. Choose the correct answer below. A. type I error B. correct decision because a true null hypothesis is not rejected C. correct decision because…
Using image attached A. Fill in blanks B. What are the null and alternative hypothesis? C. Find the test statistic, z0 D. Find the P-Value
Test the claim that the mean GPA of night students is significantly different than 2.3 at the 0.05 significance level.The null and alternative hypothesis would be: H0:μ=2.3H0:μ=2.3H1:μ>2.3H1:μ>2.3 H0:p=0.575H0:p=0.575H1:p>0.575H1:p>0.575 H0:μ=2.3H0:μ=2.3H1:μ<2.3H1:μ<2.3 H0:p=0.575H0:p=0.575H1:p≠0.575H1:p≠0.575 H0:μ=2.3H0:μ=2.3H1:μ≠2.3H1:μ≠2.3 H0:p=0.575H0:p=0.575H1:p<0.575H1:p<0.575 The test is: two-tailed left-tailed right-tailed Based on a sample of 80 people, the sample mean GPA was 2.27 with a standard deviation of 0.02The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
The Department of Agriculture wants to determine whether the mean yield per acre for a particular variety of soybeans is different this year compared to the historical avg yield of 520 bushels per acre. Thus, the null and alternative hypotheses are Ho: mu = 520 Ha: mu is not = to 520 You set out to conduct a hypothesis test at the 95% level. Mean yields are distributed Normally. You take a sample of 36 different acres. From this sample, you calculate a mean yield of 573 and a std deviation of 24. Do you reject or not-reject the null hypothesis? Group of answer choices Do not reject the null hypothesis. Reject the null hypothesis.
Fertilizer: A new type of fertilizer is being tested on a plot of land in an orange grove, to see whether it increases the amount of fruit produced. The mean number of pounds of fruit on this plot of land with the old fertilizer was 381 pounds. Agriculture scientists believe that the new fertilizer may increase the yield. State the appropriate null and alternate hypotheses. Answer the following question.
Find the p-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.10 significance level. Is the alternative hypothesis supported? Z= 0.9 for H0: u=136 pounds and Ha: u is not = 136 pounds. The p-value is ?
According to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0.1 level of significance. What is the test statistic? t-score population parameter Z-Score standard deviation
Which is NOT a correct statement about the Null hypothesis a. The average days per week that elementary students lifted weights was the same for 2011 and 2013 b. The average time spent in sedentary behaviors is not different between male and female c. The mean body mass index for adults in County A is not different from the mean body mass index in adults in County B d. The mean sleep time for 4th grade students is different from the mean sleep time for 5th grade students
The recidivism rate for convicted sex offenders is 12%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 322 convicted sex offenders who were also drug addicts, 48 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion V b. The null and alternative hypotheses would be: Ho: ? v Select an answer (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? V a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 12% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of…

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