In a study on caffeine and stress, college students (n = 10) indicated how many cups of coffee they drink per day and their stress level on a scale of 1 to 10. The research hypothesis is that there is an association between stress and cups of coffee consumed per day.
In a study on caffeine and stress, college students (n = 10) indicated how many cups of coffee they drink per day and their stress level on a scale of 1 to 10. The research hypothesis is that there is an association between stress and cups of coffee consumed per day.
Express the substantive question as two statistical hypotheses.
Report hypotheses to TWO decimal places.
H0: Answer
Answer
Answer
H1: Answer
Answer
Answer
Set the criteria for a decision. On paper draw the sampling distribution assuming the null hypothesis is true. Use p < .05 as the criterion for statistical significance to determine and label the critical values. Use the sampling distribution to answer the following questions:
What is the shape of the distribution? Answer
What is the most frequent score on the x-axis? Answer
Answer
Answer
α = Answer
2 decimal places
What are the dfs? Answer
What is the Tcv? ±Answer
3 decimal places
Use the data are below to determine the sum of scores for the predictor (SSx) the sum of squares for the outcome (SSy) and the sum of the cross-products (SP).
Table for SSx, SSy, and SP
Ps | Stress (X) | Coffee (Y) | X-Mx | Y-My | (X-Mx)2 | (Y-My)2 | (X-Mx)(Y-My) |
---|---|---|---|---|---|---|---|
1 | 5 | 3 | Answer
|
Answer
|
Answer
|
Answer
|
Answer
|
2 | 3 | 2 | Answer
|
Answer
|
Answer
|
Answer
|
Answer
|
3 | 3 | 4 | Answer
|
Answer
|
Answer
|
Answer
|
Answer
|
4 | 9 | 6 | Answer
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Answer
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Answer
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Answer
|
Answer
|
5 | 4 | 5 | Answer
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Answer
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Answer
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Answer
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Answer
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6 | 2 | 1 | Answer
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Answer
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Answer
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Answer
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Answer
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7 | 8 | 10 | Answer
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Answer
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Answer
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Answer
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Answer
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8 | 5 | 3 | Answer
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Answer
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Answer
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Answer
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Answer
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9 | 3 | 2 | Answer
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Answer
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Answer
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Answer
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Answer
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10 | 8 | 4 | Answer
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Answer
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Answer
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Answer
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Answer
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Mx = Answer
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My = Answer
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∑ = Answer
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∑ = Answer
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∑ = Answer
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∑ = Answer
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∑ = Answer
|
Use all your calculations to complete this Table of
Table of Descriptive Statistics
Statistics | Values |
---|---|
SP | Answer
42
|
SSx | Answer
56
|
SSy | Answer
60
|
n | Answer
10
|
df | Answer
8
|
r = Answer
SEr = Answer
t-test = Answer
Use the Table of Descriptive statistics, correlation (r), the standard error of the correlation (SEr), and the r to zr Table, to go through the steps to compute the 95% CI.
Report all values to TWO decimal places for the next 5 sections.
Transform r to zr:
In our table, we find that r = Answer corresponds to zr = Answer
Compute the standard error of zr
SEzr = Answer
Because this is the 95% confidence interval:
zCritical = ±Answer 3 decimal places
Compute the confidence interval around zr
Answer ± Answer(Answer) = (Answer , Answer)
We find the zr of Answer corresponds to r = Answer
We find the zr of Answer corresponds to r = Answer
Therefore, the 95% confidence interval around r = Answer is (Answer , Answer)
Using all the descriptive and
Report all values to TWO decimal places.
A Answer demonstrated there was a AnswerAnswerAnswer between coffee consumption and reported stress, AnswerAnswerAnswer. Importantly, a Answer demonstrated the association Answer statistically significant, t(Answer) = Answer, p AnswerAnswer. Also, the 95% CI Answer include 0, (Answer , Answer). Thus, as people reported Answer stress, they reported drinking Answer coffee.
Step by step
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