The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n = 899 and the test statistic is t=54.506. Use technology to find the P-value. Basedon the result, what is the final conclusion? Use a significance level of 0.10State the null and alternative hypotheses.HouH₂H ▼(Type integers or decimals. Do not round.)The test statistic is(Round to two decimal places as needed.)The P-value is(Round to three decimal places as needed.)Based on the P-value, theresufficient evidence at a significance level of 0.10 toCthe claim that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers.

Answered: Image /qna-images/answer/02b42942-0225-4575-abee-21180d5900e2.jpg

Answered: The claim is that smokers have a mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If applicable, use the appropriate test to determine the average nicotine content which differs. In responding, construct and test any appropriate hypothesis.
The US Department of Energy reported that 48% of homes were heated by natural gas. A random sample of 331 homes in Oregon found that 132 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0: H1: Based on the hypotheses, compute the following:Test Statistic = p-value = Based on the above we choose to The correct summary would be: that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 48%.
Please please answer that
Four brands of lightbulbs are being considered for use in the final assembly area of the Ford F-150 truck plant in Dearborn, Michigan. The director of purchasing asked for samples of 100 from each manufacturer. The numbers of acceptable and unacceptable bulbs from each manufacturer are shown below. At the .05 significance level, is there a difference in the quality of the bulbs? (Round your answers to 3 decimal places.) H0: There is no relationship between quality and manufacturer. H1: There is a relationship. 1. Reject H0 if X2 >____ 2. X2 = ____ (Reject or Do Not Reject) H0. Ther (is a/is no) relationship between quality and manufacturer.
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.03, 37.45, 36.75, 37.54, 37.71, 37.02, 37.32 Pond 2: 38.89, 39.05, 38.51, 38.53, 38.71 Use a 2% significance level to test the claim that the two ponds have the same mean salinity value. Assume that nothing is known about the population distribution of salinities. (a) Enter the rank values in the same order as in the original sample. The rank values for Pond 1 are: The rank values for Pond 2 are: (b) The test statistic is: . (c) The test critical value is: . (d) The conclusion isA. There is not sufficient evidence to indicate that the two ponds have different distributions of salinity values.B. There is sufficient evidence to indicate that the two ponds have different distributions of salinity values.
You want to compare differences in prior arrests across ethnicity in your study, you measured ethnicity as white =0 black =1 hispanic=2, and other =3. Prior arrests was recorded as the number of prior arrests. which test would you perform to see if arrests differ across diffrent ethnic categories? A. ANOVA B. T-test
options for first to blanks : 1- between 0.05 and 0.20 /2- greater than 0.20 / 3- less than 0.2 options for last blank : 1- handrubbing with alcohol / 2- handwashing with soap
Using a significance level of α = 0.05, state your conclusion in terms of H0.?
According to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0.1 level of significance. What is the test statistic? t-score population parameter Z-Score standard deviation
A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?

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