The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure tonicotine.) The sample size is n = 911 and the test statistic is t= 56.944. Use technology to find the P-value. Based on the result, what is the final conclusion? Use asignificance level of 0.01.State the null and alternative hypotheses.Hot = 2.84H₁: > 2.84(Type integers or decimals. Do not round.)The test statistic is 56.94.(Round to two decimal places as needed.)The P-value is.(Round to three decimal places as needed.)C

given data, claim : μ>2.84n=911t= 56.944p-value =?α=0.01we have to find out the p-value and…

Answered: The claim is that smokers have a mean…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Red Blood Cell Count: A simple random sample of 300 adult males is taken to measure the red blood cell count (in cells per microliter). Use a significance level of 0.01 to test the claim that the sample has a mean less than the population mean (μ = 5.4 million cells per microliter). Does the sample have a normal distribution? Explain why. Does the result suggest that the male sample has a red blood cell count below 5.4 million cells per microliter? Determine the descriptive statistics of the sample. State the statistical hypotheses: H0 and HA. Determine the α Is this test one or two tailed? What statistical conclusion did you reach regarding the question being evaluated? RED 4.80 4.73 4.47 4.32 4.95 3.95 4.68 4.60 4.09 5.47 4.44 4.15 5.07 4.38 5.22 4.22 4.32 4.30 6.34 5.60 4.93 5.18 3.54 4.61 4.22 4.99 5.23 4.01 4.07 5.06 4.30 4.28 4.76 4.14 4.61 4.67 4.36 4.28 4.59 4.77 3.86 5.38 5.03 4.60…
The claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers. (Cotinine is used as a biomarker for exposure to nicotine.) The sample size is n 810 and the test statistic is t=55.337. Use technology to find the P-value. Based on the result, what is the final conclusion? Use a significance level of 0.01. State the null and alternative hypotheses. Ho H H₁H (Type integers or decimals. Do not round.)
For the specified margin of error and confidence level, obtain a sample size that will ensure a margin of error of at most the one specified. margin of error = 0.03; confidence level = 90% Click here to view Page 1 of the table of areas under the standard normal curve. Click here to view Page 2 of the table of areas under the standard normal curve. n= (Round up to the nearest integer.)
Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 18 mu g/g. Assume that the sample is a simple random sample. a. Determine the test statistic. (Round to two decimal places as needed.) b. Determine the P-value. (Round to three decimal places as needed.)
A manufacturing company wants to see if there is a significant difference in three types of plastic for a new product. They randomly sample prices for each of the three types of plastic and run an ANOVA. Use α = 0.05 to see if there is a statistically significant difference in the mean prices. Part of the computer output is shown below, fill in the missing information. Use alpha= 0.01. a. Compute the test statistic. Fill out the entire ANOVA table. Round answers to at least 4 decimal places. Sample Mean Sample Size High-Density Polythene 38.5673 11 Low-Density Polythene 38.0473 15 Polyethylene Terephthalate 35.8375 8 Source S.S. df M.S. F Treatment Incorrect Correct Incorrect Incorrect Error Incorrect Correct 6.69797 Total 245.471038 Correct b. What is the critical value? Incorrect c. What is the correct decision?
use the t- distribution and the sample results to complete the test of the hypothesis. use a 5% significance level. Assume the results come from a random sample , and if the sample size is small, assume the underlying distribution is relatively normal . H0: miu=4 vs Ha: miu not equal to 4 using the sample results x bar =4.8 s= 2.3 with n=15. WHAT IS THE P-VALUE?
The p-value for a t-statistic was .008. What is the best way to report the level of significance? p<.008 p<.05 p<.01 p<.001
Assume that the significance level is α=0.1. Use the given information to find the P-value and the critical value(s).The test statistic of z=1.81 is obtained when testing the claim that p>0.2.Click here to view page 1 of the Normal table. LOADING... Click here to view page 2 of the Normal table. LOADING...Question content area bottomPart 1P-value=enter your response here (Round to four decimal places as needed.)Part 2The critical value(s) is/are z=enter your response here.(Round to two decimal places as needed. Use a comma to separate answers as needed.)
1. What is the value of the standardized test statistic? 2. What is the P-value?
Find the percentage of the total area under the standard normal curve between the following z-scores. z=1.44 and z=2.83 Click here for page 1 of the Areas under the Normal Curve Table Click here for page 2 of the Areas under the Normal Curve Table The percentage of the total area between z=1 44 and z=2.83 is% (Round to two decimal places as needed.)
Please answer the questions in the photo. For Question 1, B has been selected BUT that could possibly not be the right answer. Please select the correct answer for Question 1 & 2.
What is the standardized test statistic t for a sample with n = 12, xbar = 30.2, s = 2.2, and α = 0.01 if H0: µ =29? Round your answer to the nearest thousandth.

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