The amount of water usage at a water park for a random sample of 21 days yeilded sample mean of 245.2238 thousands gallons per day and sample standard deviation of 40.8096 thousand gallons per day. Is there any evidence, at the level of significance 0.01, to suggest that the mean water usage at this park is different from 250 thousand gallons per day? Let T = (bar{X} - 250)/ (S/sqrt{21}), where bar{X} is the sample mean S is the sample standard deviation, sqrt{21} is the square root of 21. Group of answer choices Since |T| = 0.5396 < t0.005 (20) = 2.845, there is enough evidence to suggest that the park water usage is different from 250 thousand gallons per day. Since |T| = 0.5396 < t0.005 (20) = 2.845, there is not enough evidence to suggest that the park water usage is different from 250 thousand gallons per day. Since T = - 0.5396 < t0.01 (20) = 2.528, there is enough evidence to suggest that the park water usage is different from 250 thousand gallons per day
The amount of water usage at a water park for a random sample of 21 days yeilded sample mean of 245.2238 thousands gallons per day and sample standard deviation of 40.8096 thousand gallons per day. Is there any evidence, at the level of significance 0.01, to suggest that the mean water usage at this park is different from 250 thousand gallons per day?
Let T = (bar{X} - 250)/ (S/sqrt{21}),
where
bar{X} is the sample mean
S is the sample standard deviation,
sqrt{21} is the square root of 21.
Since |T| = 0.5396 < t0.005 (20) = 2.845, there is enough evidence to suggest that the park water usage is different from 250 thousand gallons per day.
Since |T| = 0.5396 < t0.005 (20) = 2.845, there is not enough evidence to suggest that the park water usage is different from 250 thousand gallons per day.
Since T = - 0.5396 < t0.01 (20) = 2.528, there is enough evidence to suggest that the park water usage is different from 250 thousand gallons per day
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