Majesty Video Production Inc. wants the mean length of its advertisements to be 31 seconds. Assume the distribution of ad length follows the normal distribution with a population standard deviation of 2 seconds. Suppose we select a sample of 19 ads produced by Majesty. (Z values and final answers should be rounded to two decimal places) - I got that the standard error is 0.46 given 2/sqrt(19) - However, when solving for Z-values using (X - mean)/standard error, I got values more than 3. I figured since they're so close to being .5 from the 0 in a normal curve, it would round to .5. c. What percent of the sample means will be greater than 32.50 seconds? d. What percent of the sample means will be greater than 29.25 seconds? e. What percent of the sample means will be greater than 29.25 but less than 32.50 seconds?
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
Majesty Video Production Inc. wants the
(Z values and final answers should be rounded to two decimal places)
- I got that the standard error is 0.46 given 2/sqrt(19)
- However, when solving for Z-values using (X - mean)/standard error, I got values more than 3. I figured since they're so close to being .5 from the 0 in a normal curve, it would round to .5.
c. What percent of the sample means will be greater than 32.50 seconds?
d. What percent of the sample means will be greater than 29.25 seconds?
e. What percent of the sample means will be greater than 29.25 but less than 32.50 seconds?
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
