The nicotine content in cigarettes of a certain brand is normally distributed with mean (n milligrams) u and standard deviation o = 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 15 cigarettes of this brand. The sample yields an average of 1.55 mg of nicotine. Conduct a test using a significance level of a = 0.05. (a) The test statistic (b) The critical value, z" (c) The final conclusion is There is evidence that the mean nicotine content is higher than advertised. There is not sufficient evidence show that the mean nocitine content is higher than advertised.

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The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) u and standard deviationo = 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine
content is actually higher than advertised. He takes measurements from a SRS of 15 cigarettes of this brand. The sample yields an average of 1.55 mg of nicotine. Conduct a test using a significance level of a = 0.05.
(a) The test statistic
(b) The critical value, z=
(c) The final conclusion is
O A. There is evidence that the mean nicotine content is higher than advertised.
O B. There is not sufficient evidence to show that the mean nocitine content is higher than advertised.
Transcribed Image Text:The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) u and standard deviationo = 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 15 cigarettes of this brand. The sample yields an average of 1.55 mg of nicotine. Conduct a test using a significance level of a = 0.05. (a) The test statistic (b) The critical value, z= (c) The final conclusion is O A. There is evidence that the mean nicotine content is higher than advertised. O B. There is not sufficient evidence to show that the mean nocitine content is higher than advertised.
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