Pulse rates of adult men are approximately normal with a mean of 70 and astandard deviation of 8. Which choice correctly describes how to find the proportionof men that have a pulse rate greater than 78?(a) Find the area to the right of z = -1 under a standard normal curve.(b) Find the area to the right of z=1 under a standard normal curve.(c) Find the area to the left of z = 1 under a standard normal curve.(d) Find the area between z=-1 and z=1 under a standard normal curve.(e) None of the above

The formula of z score when the data is normally distributed is given by Where, x =…

Answered: Pulse rates of adult men are…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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n=16 mean number of television per household is 4 with a standard deviation of 1 television. using chebychev's theorem, detemine at least how many households have between 2 and 6 television.
Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.t Over a period of months, an adult male patient has taken seven blood tests for uric acid. The mean concentration was x = 5.29 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with o = 1.95 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) On is large O o is known O o is unknown O normal distribution of uric acid O uniform distribution of uric acid (c) Interpret your results in the context of this problem. O we are 95% confident that the true uric acid level for this patient falls within this interval. O we are 5% confident that…
A normal distribution with a mean of 2mm and a standard deviation of 0.05mm a randomly generated number of 0.71 , need to calculate the standardised Z value, from my notes Z = (actual value - mean)/standard deviation. do i take the randomly generated number of 0.81 as the actual value ?
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. A symmetric bell-shaped curve is plotted over a horizontal scale. A vertical line runs from the scale to the curve at labeled coordinate 84, which is to the left of the curve’s center and peak. The area under the curve to the right of the vertical line is shaded. The area of the shaded region is (Round to four decimal places as needed.)
Help me please
uestion 2: Write uses of the standard deviation
Use the information to make a normal distribution using the Empirical Rule, label the mean and three standard deviations from the mean.
Use the formula to find the standard error of the distribution of differences in sample means, I – X2. Samples of size 270 from Population 1 with mean 74 and standard deviation 18 and samples of size 510 from Population 2 with mean 88 and standard deviation 24 Round your answer for the standard error to two decimal places. standard error =
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 102 126 A symmetric bell-shaped curve is plotted over a horizontal scale. Two vertical lines run from the scale to the curve at labeled coordinates 102 and 126, which are both to the right of the curve’s center and peak. The area under the curve between the vertical lines is shaded. The area of the shaded region is enter your response here. (Round to four decimal places as needed.)
Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.t Over a period of months, an adult male patient has taken nine blood tests for uric acid. The mean concentration was x = 5.41 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with o = 1.75 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.) lower limit upper limit margin of error (b) What conditions are necessary for your calculations? (Select all that apply.) normal distribution of uric acid On is large O o is unknown O uniform distribution of uric acid O o is known (c) Interpret your results in the context of this problem. The probability that this interval contains the true average uric acid level for this patient is 0.95. The probability that this…
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. 108 124 The area of the shaded region is (Round to four decimal places as needed.)
The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…

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