The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion?-..State the null and alternative hypotheses in the test for the effect of an interaction between row and column factors.Ho: ThereH₁: ThereWhat is the value of the test statistic for this test?F = (Round to two decimal places as needed.)What is the corresponding P-value of the test statistic, F, for this test?P-value= (Round to three decimal places as needed.)State the conclusion of this test.Ho. There ▼ sufficient evidence to warrant rejection of the claim that pulse rates are not affected by an interaction between gender and age. ThereState the null and alternative hypotheses in the test for the effect from the row factor.O A. Ho: The row values are from populations with the same mean.H₁: At least one of the rows is sampled from a population with a mean different from the others.interaction between gender and age.interaction between gender and age.O B. Ho: The row values are from populations with the same standard deviation.H₁: At least one of the rows is sampled from a population with a standard deviation different from the others.O C. Ho: At least one of the rows is sampled from a population with a mean different from the others.H₁: The row values are from populations with the same mean.O D. In this case, the test for the effect from a row factor should not be done.What is the value of the test statistic for this test?OA. F=(Round to two decimal places as needed.)O B. In this case, the test for the effect from a row factor should not be done.What is the corresponding P-value of the test statistic, F, for this test?COA. P-value =(Round to three decimal places as needed.)O B. In this case, the test for the effect from a row factor should not be done.appear to be an effect from an interaction between gender and age.Pulse Rates for Gender and AgeUnder 30 Years of AgeOver 30 Years of AgeFemale 78 105 79 64 61 98 81 98 90 95 75 76 72 66 73 78 62 72 73 55 FemaleMale 60 81 56 68 68 74 74 68 62 55 46 71 63 65 91 80 60 57 63 61 MalePrintDoneD- X The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion?State the conclusion of this test. Choose the correct answer below.O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the row values are from populations with the same standard deviation.O B. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the row values are from populations with the same mean.O C.Do not reject Ho. There is insufficient evidence to warrant rejection of the claim that the row values are from populations with the same standard deviation.O D. Do not reject Ho. There is insufficient evidence to warrant rejection of the claim that the row values are from populations with the same mean.O E. In this case, the test for the effect from a row factor should not be done.State the null and alternative hypotheses in the test for the effect from the column factor.O A. Ho: The column values are from populations with the same standard deviation.H₁: At least one of the columns is sampled from a population with a standard deviation different from the others.O B. Ho: The column values are from populations with the same mean.H₁: At least one of the columns is sampled from a population with a mean different from the others.O C. Ho: At least one of the columns is sampled from a population with a mean different from the others.H₁: The column values are from populations with the same mean.O D. In this case, the test for the effect from a column factor should not be done.What is the value of the test statistic for this test?O A. F=(Round to two decimal places as needed.)O B. In this case, the test for the effect from a column factor should not be done.What is the corresponding P-value of the test statistic, F, for this test?COA. P-value=(Round to three decimal places as needed.)O B. In this case, the test for the effect from a column factor should not be done.State the conclusion of this test.Pulse Rates for Gender and AgeUnder 30 Years of AgeOver 30 Years of AgeFemale 78 105 79 64 61 98 81 98 90 95 75 76 72 66 73 78 62 72 73 55 FemaleMale 60 81 56 68 68 74 74 68 62 55 46 71 63 65 91 80 60 57 63 61 MaleO A. Do not reject Ho. There is insufficient evidence to warrant rejection of the claim that the column values are from populations with the same mean.PrintDone-X

Given information: Under 30 Years of Age Over 30 years of Age Female 78 75 105 76 79 72 64 66 61 73 98 78 81 62 98 72 90 73 95 55 Male 60 46 81 71 56 63 68 65 68 91 74 80 74 60 68 57 62 63 55 61 a) Perform the Anova: Two-Factor With Replication using the excel: Step 1) Click the Data tab > Data Analysis. Step 2) Select Anova: Two-Factor With Replication and click OK. Step 3) Click the up arrow next to Input Range. Step 4) Select the data and click the down arrow. Step 5) Enter "10" for Rows per sample Step 5) Click OK to run the analysis. Anova: Two-Factor With Replication SUMMARY Under 30 Years of Age Over 30 years of Age Total Female Count 10 10 20 Sum 849 702 1551 Average 84.9 70.2 77.55 Variance 220.1 50.62222222 185.1026316 Male Count 10 10 20 Sum 666 657 1323 Average 66.6 65.7 66.15 Variance 70.48888889 156.2333333 107.6078947 Total Count 20 20 Sum 1515 1359 Average 75.75 67.95 Variance 225.7763158 103.3131579 ANOVA Source of Variation SS df MS F P-value Sample 1299.6 1 1299.6 10.4502122 0.002625218 Columns 608.4 1 608.4 4.892204601 0.033411811 Interaction 476.1 1 476.1 3.82836721 0.058183276 Within 4477 36 124.3611111 Total 6861.1 39 a) Null hypothesis: H0 : There is no interaction between gender and age. Alternative hypothesis: HA : There is interaction between gender and age. For this analysis, the significance level is 0.05. Analyse sample data. F statistics is given by:- F=MSInteractionMSWithin =476.1124.3611111=3.82836721≈3.83 Use the excel formula, "=F.DIST.RT(2.83,1,36)" to determine the P-value: The P-value = 0.0582 Interpret results. Since the P-value (0.0582) is greater than the significance level (0.05), we failed to reject the null hypothesis. Conclusion:- Failed to reject H0, There is not sufficient evidence to warrant rejection of the claim that pulse rates are not affected by an interaction between gender and age. There does not appears to be an effect from an interaction between gender and age.b) (A) Null hypothesis: H0 : The row values are from population with the same mean. Alternative hypothesis: HA : At-least one of the rows is sampled from a population with a mean different from the others. For this analysis, the significance level is 0.05. F statistics is given by:- F=MSRowsMSWithin =1299.6124.3611111=10.4502122=10.45 Use the excel formula, "=F.DIST.RT(10.45,1,36)" to determine the P-value: The P-value = 0.003 Interpret results. Since the P-value (0.003) is less than the significance level (0.05), we have to reject the null hypothesis. Conclusion:- (B) Reject H0, There is sufficient evidence to warrant rejection of the claim that the row values are from the population with the same mean.c) (B) Null hypothesis: H0 : The column values are from population with the same mean. Alternative hypothesis: HA : At-least one of the column is sampled from a population with a mean different from the others. For this analysis, the significance level is 0.05. F statistics is given by:- F=MSColumnMSWithin =608.4124.361111=4.892204601=4.89 Use the excel formula, "=F.DIST.RT(4.89,1,36)" to determine the P-value: The P-value = 0.033 Interpret results. Since the P-value (0.033) is less than the significance level (0.05), we have to reject the null hypothesis. Conclusion:- Reject H0, There is sufficient evidence to warrant rejection of the claim that the column values are from the population with the same mean.

Math

Statistics

The accompanying table lists pulse rates. Use a 0.05 significance level and apply the methods of two-way analysis of variance. What is the conclusion? State the null and alternative hypotheses in the test for the effect of an interaction between row and column factors. interaction between gender and age. interaction between gender and age. Ho: There H₁: There "What is the value of the test statistic for this test? F=(Round to two decimal places as needed.) "What is the corresponding P-value of the test statistic, F, for this test? P-value = (Round to three decimal places as needed.) State the conclusion of this test. Ho. There sufficient evidence to warrant rejection of the claim that pulse rates are not affected by an interaction between gender and age. There State the null and alternative hypotheses in the test for the effect from the row factor. OA. Ho: The row values are from populations with the same mean. H₁: At least one of the rows is sampled from a population with a mean different from the others. OB. Ho: The row values are from populations with the same standard deviation. H₁: At least one of the rows is sampled from a population with a standard deviation different from the others. OC. Ho: At least one of the rows is sampled from a population with a mean different from the others. H₁: The row values are from populations with the same mean. OD. In this case, the test for the effect from a row factor should not be done. "What is the value of the test statistic for this test? OA. F= (Round to two decimal places as needed.) OB. In this case, the test for the effect from a row factor should not be done. What is the corresponding P-value of the test statistic, F, for this test? OA. P-value = (Round to three decimal places as needed.) OB. In this case, the test for the effect from a row factor should not be done. appear to be an effect from an interaction between gender and age. Pulse Rates for Gender and Age Under 30 Years of Age Over 30 Years of Age Female 78 105 79 64 61 98 81 98 90 95 75 76 72 66 73 78 62 72 73 55 Female Male 60 81 56 68 68 74 74 68 62 55 46 71 63 65 91 80 60 57 63 61 Male Print Done - X