The absorbance of a sample of erioglaucine was measured to be 0.525through a 10mm cuvette. The concentration of the sample was alsodetermined to be 7.85 x 10 M. Determine the molar absorptivity oferioglaucine. (Report answer to the ones place regardless of sig figs.)"Only use numeric values in your answer. Do not use words, spaces, orsymbols (ie. %).**

The relationship between the absorbance (A) and the concentration (X) of a solution is furnished by…

The absorbance of a sample of erioglaucine was measured to be 0.525 through a 10mm cuvette. The concentration of the sample was also determined to be 7.85 x 106M. Determine the molar absorptivity of erioglaucine. (Report answer to the ones place regardless of sig figs.) *"Only use numeric values in your answer. Do not use words, spaces, or symbols (ie. %).**

The absorbance of a sample of erioglaucine was measured to be 0.525 through a 10mm cuvette. The concentration of the sample was also determined to be 7.85 x 106M. Determine the molar absorptivity of erioglaucine. (Report answer to the ones place regardless of sig figs.) *"Only use numeric values in your answer. Do not use words, spaces, or symbols (ie. %).**

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The absorbance of a sample of erioglaucine was measured to be 0.525
through a 10mm cuvette. The concentration of the sample was also
determined to be 7.85 x 10 M. Determine the molar absorptivity of
erioglaucine. (Report answer to the ones place regardless of sig figs.)
"Only use numeric values in your answer. Do not use words, spaces, or
symbols (ie. %).**

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Report table 2: Determination of Molar absorptivity of K2CrO4 ppm of K2CrO4 in "DILUTE STOCK (5mL/50mL)"=1.5012 Molarity of K:CrO4 in "DILUTE STOCK(5mL/50mL)" = 7.7319× 10^-3 Peak wavelength λmax=372 nm From single wavelength values Peak Absorbance From spectrum A = 0.487 8=> 1 2 3 4 A= 0.370 A=0.434 A= 0.487 A= 0.347 8= 8= 8= 1.2864×10^6 1.5171×10^6 1.7023×10 6 1.20642×10^6 Average & (for the 4 readings) Standard deviation of a 95% Confidence interval of a = 1.428055×10^6 Show sample calculation (for solution 1): = A/b.c = Molar Absorption= 0,370/(3.72*10^-5)(7.7319× 10^-3)= 1.2864×10^6 M^-1cm^-1
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SPECTROPHOTOMETRY Two groups in a BIO 120 lab extracted a blue-violet pigment from mayana plant which was to be used as a natural dye for Philippine textiles. To determine the concentration of the pigment isolated, each group made a standard curve using commercially available indigo dye in dimethylsulfoxide (DMSO). The following data were obtained by the two groups: Table 4. Absorbance readings of standard solutions of varying concentrations of indigo dye in DMSO. Pure DMSO 0.115 Standard solutions (ppm) Group 1 Data Group 2 Data 0.2 0.398 0.224 0.4 0.563 0.437 0.6 0.732 0.603 0.8 0.833 0.811 1.0 1.008 0.966 1. Show the constructed standard curves of the two groups with proper figure titles. 2. Which of the two groups generated a better standard curve? Justify your answer by providing the R? value for each data set. 3. The extracted pigment has an absorbance of 0.983. When a 0.2 mL-aliquot of the extract was diluted to 1.0 mL, the absorbance of the diluted solution was found to be…
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