TEST YOURUNDERSTANDING!The tension stress-strain diagram for a square bar (50 x 50mm²; L = 600 mm) is shown in the figure. If the applied load is500 kN, determine the elongation and the new side length ofthe specimen. The shear modulus is G = 83 GPa.1. What is the modulus of elasticity of the material?2. What is the Poisson's ratio of the material?3. What is the lateral strain of the material?Answer to Test your understanding box1.200 GPa2.3.4.(MPa)0.20482.048 x 10449.9898 mm4000.002(TYU 2-2)What is the new side length of the material?5.If a force applied to the material elongates the material by 3 mm, what happens to thematerial if the force is removed? Why?(mm/mm)

Answered: Image /qna-images/answer/64455348-5775-4500-98a7-c5b4cf26d5f3.jpg

TEST YOUR UNDERSTANDING! The tension stress-strain diagram for a square bar (50 x 50 mm²; L = 600 mm) is shown in the figure. If the applied load is 500 kN, determine the elongation and the new side length of the specimen. The shear modulus is G = 83 GPa. 1. What is the modulus of elasticity of the material? 2. What is the Poisson's ratio of the material? Answer to Test your understanding box 1. 200 GPa 2. 3. (MPa) 0.2048 2.048 x 104 49 9898 mm 400 0.002 (TYU 2-2) 3. What is the lateral strain of the material? 4. What is the new side length of the material? 5. If a force applied to the material elongates the material by 3 mm, what happens to the material if the force is removed? Why? ←(mm/mm)

TEST YOUR UNDERSTANDING! The tension stress-strain diagram for a square bar (50 x 50 mm²; L = 600 mm) is shown in the figure. If the applied load is 500 kN, determine the elongation and the new side length of the specimen. The shear modulus is G = 83 GPa. 1. What is the modulus of elasticity of the material? 2. What is the Poisson's ratio of the material? Answer to Test your understanding box 1. 200 GPa 2. 3. (MPa) 0.2048 2.048 x 104 49 9898 mm 400 0.002 (TYU 2-2) 3. What is the lateral strain of the material? 4. What is the new side length of the material? 5. If a force applied to the material elongates the material by 3 mm, what happens to the material if the force is removed? Why? ←(mm/mm)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Rigid bar ABCD is loaded and supported as shown. Steel [E = 29800 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.86 in.² and bar (2) has a cross-sectional area of 0.47 in.2. After load P is applied, the strain in bar (1) is found to be 780 μe. Assume L₁-52 in., L₂=74 in., a=20 in., b=25 in., and c-33 in. Determine: (a) the stresses in bars (1) and (2). (b) the vertical deflection vp of point D on the rigid bar. (c) the load P. Answers: (a) σ1 (b) VD=i (c) P = i L eTextbook and Media Save for Later (1) B L2 b (2) ksi, 0₂ = in. kips. i D P ksi. Attempts: 0 of 5 used Submit Answer
An axial load P is applied to a 150"-long continuous bar with the cross-sectional areas (4) shown in the figure below. The stress-strain relation of the material used to make this bar obtained during a tension test can be expressed as follows: P € = A = 1 in² -50"- O 16000 where o is the normal stress in ksi. a) Determine the axial elongation (in inches) and strain (in %) of the bar when P = 5 kips. b) Find the permanent elongation (in inches) and strain (in %) of the bar after removal of P in a). + (165)³ A = ¹in² 100"- P Note: You can assume that the elastic modulus (E) of material of the bar is equal, at all times, to the slope of the stress-strain curve at the origin.
Consider the pre-deformation cross-section of a bar, a side view of which is shown in the figure below. h ΫΠ' ΑΣΦ D The diameter of the bar is d = 230 mm. A bending moment is applied that causes the neutral axis to become concave up. What is the normal strain h = 40 mm from the bottom of the bar if the radius of curvature is measured to be p = 6.7 m? Express your answer to three significant figures. ► View Available Hint(s) Ax ↓↑ vec t O ? mm/mm
Determine the elastic tensile load "F" that acts on mild steel specimen of Diameter 8 mm & Modulus of Elasticity 201 GPa. It is found that the specimen has undergone an extension of 1.6 mm due to the elastic load "F". Also, determine the length "L" of the specimen, if the strain-induced due to the load "F" on the specimen is 4.1 x 10-3. Solution Cross-sectional Area, A (in mm²) Tensile Load, F (in N) Length of the Specimen (in mm)
QUESTION 2 The rigid bar ACE is supported by two steel rods AB and CD (Esteel = 200 GPa) with the cross sectional areas of each rod is given as shown in Figure Q2. (a) Determine the position d of the 30 kN load so that the average normal stress in each rod is the same. (b) Find the strain in rod CD, ɛcD (c) Determine the horizontal displacement of point E 1.2 m ACD = 600 mm? 0.8 m E 30 kN AAB = 900 mm2 d B 1.8 m Figure Q2
When an axial load is applied to the ends of the bar shown in the figure, the total elongation of the bar between joints A and C is 0.17 in. In segment (2), the normal strain is measured as 1,450 uin./in. Assume L₁ - 45 in. and L₂ - 94 in. Determine (a) the elongation of segment (2). (b) the normal strain in segment (1) of the bar. P A Answers: L₁ (a) in.₂ = i (b) £₁ = i B (2) L2 in. uin./in.
Rigid bar ABCD is loaded and supported as shown. Steel [E = 30800 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.78 in.2 and bar (2) has a cross-sectional area of 0.32 in.2. After load P is applied, the strain in bar (1) is found to be 610 μεμε. Assume L1=50 in., L2=76 in., a=28 in., b=21 in., and c=22 in. Determine:(a) the stresses in bars (1) and (2).(b) the vertical deflection vD of point D on the rigid bar.(c) the load P.
O 0.6% 19% If an isotropic material has a Young's modulus of 85 Gpa and a Poisson's ratio of 0.25, calculate its shear modulus. Select one: O G = 29 Gpa O G = 34 Gpa G = 25 Gpa O G= 77 Gpa O G= 46 Gpa If a rubber material is deformed as shown in the following figure, determine the normal strain along diagonal BD. C 2 mm 4 mm EN DO O
Determine the elastic tensile load "F" that acts on mild steel specimen of Diameter 5 mm & Modulus of Elasticity 207 GPa. It is found that the specimen has undergone an extension of 1.2 mm due to the elastic load "F". Also, determine the length "L" of the specimen, if the strain-induced due to the load "F" on the specimen is 3 x 10-³. Solution Cross-sectional Area, A (in mm²) = Tensile Stress, (in N/mm²) = Tensile Load, (in N) = Length of the Specimen (in mm)
Determine the elastic tensile load "F" that acts on mild steel specimen of Diameter 9 mm & Modulus of Elasticity 205 GPa. It is found that the specimen has undergone an extension of 1.7 mm due to the elastic load "F". Also, determine the length "L" of the specimen, if the strain-induced due to the load "F" on the specimen is 3.7 x 10-3. Solution Cross-sectional Area, A (in mm2) Tensile Load, F (in N) Length of the Specimen (in mm)
The elastic portion of the stress-strain diagram for an aluminum alloy is shown in the figure below (Figure 1). The specimen from which it was obtained has an original diameter of 12.7 mm and a gage length of 50.5 mm. Take v=0.35 Figure σ (MPa) 490 0.007 € (mm/mm) Part A If a load of P = 40 kN is applied to the specimen, determine its new diameter. Express your answer to four significant figures and include appropriate units. d= Submit Part B L= O Value Submit μA Request Answer Determine its length. Express your answer to four significant figures and include appropriate units. Provide Feedback Value Units Request Answer ? Units ?
The normal strain in a suspended bar of material of varying cross section due to its own weight is given by the expression yy/3E where y = 3.0 lb/in.³ is the specific weight of the material, y = 6.3 in. is the distance from the free (i.e., bottom) end of the bar, L = 21 in. is the length of the bar, and E = 27000 ksi is a material constant. Determine, (a) the change in length of the bar due to its own weight. (b) the average normal strain over the length L of the bar (c) the maximum normal strain in the bar. Answer: (a) d = i (b) avg (c) Emax i x10-6 in. με με